How Does the Third Piece's Velocity Compare After the Clay Ball Shatters?

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Homework Statement



A 6-kg clay ball is thrown directly against a perpendicular brick wall at a velocity of 22 m/s and shatters into three pieces, which all fly backward, as shown in the figure. The wall exerts a force on the ball of 2430 N for 0.1 s. One piece of mass 2 kg travels backward at a velocity of 15 m/s and an angle of 32° above the horizontal. A second piece of mass 1 kg travels at a velocity of 7 m/s and an angle of 28° below the horizontal. What is the velocity of the third piece? (Let up be the +y positive direction and to the right be the +x direction.)

Homework Equations



Initial momentum = Final momentum + impulse delvered by the wall.

The Attempt at a Solution



22 = x + 2430 ? I came out with -2408 and I believe it's incorrect.
 
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perfectlovehe said:
Initial momentum = Final momentum + impulse delvered by the wall.
I would write it differently:
Initial momentum + impulse delvered by the wall = Final momentum

You'll use this to find the total momentum of all pieces of the ball after the ball shatters.

22 = x + 2430 ? I came out with -2408 and I believe it's incorrect.
What's the initial momentum of the ball? What's the impulse? (Be sure to give the correct signs, since momentum is a vector and direction matters.)
 
Initial momentum is 22m/s and force is 2430 J. So would that be 2452 J? Or is that incorrect?

Initial momentum is 22m/s and force is 2430 J. So would that be 2452 J? Or is that incorrect?
 
That's incorrect. One step at a time:
(1) What's the definition of momentum? Calculate the initial momentum of the ball. What direction is the momentum? What sign?
(2) What's the definition of impulse? Calculate the impulse given to the ball. What direction is the impulse? What sign?