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Finding velocity of lump of clay. (Not too sure on answer)

  1. Apr 23, 2016 #1
    1. The problem statement, all variables and given/known data
    Two lumps of clay, each with the same mass 3.5 kg, are sliding on ice, with no friction. One is moving at 4.8 m/s to the right, the other is moving at 2.3 m/s to the left. They collide and stick to one another. Calculate the velocity of the lump of clay after the collision. Is the total kinetic energy constant?

    2. Relevant equations
    (m1+m2)vf=m1v1+m2v2

    3. The attempt at a solution
    Substituted m1 and m2=3.5 kg, v1=-2.3 m/s, and v2=4.8 m/s. With that, I got vf=1.25 m/s. I'm almost sure that one of the velocity is negative since one lump of clay is moving in the opposite direction away from the other. For the second question of whether or not total kinetic energy is constant, I said no.
     
  2. jcsd
  3. Apr 23, 2016 #2

    ehild

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    Homework Helper
    Gold Member

    The final speed is correct, but you should state, what is the direction of it.
    Yes, the kinetic energy is not conserved, but you should show its numerical value. Did it increased or decreased with respect to the initial one?
     
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