TrickyDicky said:
Correct me if I'm wrong but singularities may be viewed as. discontinuities, at least in the wikipdia page about singularity theory they are defined as failures of the manifold structure, in which case they would affect the topology. But even in the case one decides this is not the case, it is clear that at the very least it affects the differential structure, and we wouldn't be dealing with smooth manifold in its presence.
The things you mention about GR wouldn't be affected, but all the physical assertions in GR either for cosmological or asymptotically flat cases that deal with the manifold globally would.
I am going to give examples to try and illustrate what micromass and kevinferreira have written.
micromass said:
I don't get this. A manifold has a topology. Only then do we introduce a metric tensor. So the metric tensor is an extra structure.
How can an extra structure possibly change the topology of a manifold??
kevinferreira said:
As micromass pointed out, the singularities are metric tensor's singularities, not topological! The topology is only used in GR in order to be able to define open sets and local coordinates on them. And this you may always do, I think, the singularities that arise in GR do not affect this in no way.
As a differentiable manifold, what is the spacetime of an open Friedmann-Lemaitre-Robertson-Walker universe? This differentiable manifold is \mathbb{R}^4. There is no problem with topological or manifold structure, yet this spacetime is singular.
As far as I know, there is no reasonably generic, accepted definition of "spacetime singularity". There is, however, a reasonably generic definition of "singular spacetime". A rough, sufficient condition: spacetime is singular if there is a timelike curve having bounded acceleration that ends in the past or the future after a finite amount of proper time. For example, and speaking very loosely, a spacetime is singular if a person can get in a rocket, and, after using a finite amount of fuel wristwatch time, can fall "off of spacetime" at a "singularity".
The example of an open FLRW universe shows that "singular" is due to the extra structure of a pseudo-Riemannian metric tensor field.
micromass said:
My guess is that the distance is just not a very useful one as it won't agree with the pseudo-Riemannian metric. ... In the same way, we can endow a distance on a spacetime. But nothing tells us that this distance actually has a physical significance or that it agrees with some metric tensor.
As \mathbb{R}^4, clearly, we can introduce a positive-definite distance function on open FLRW universes, but, as micromass notes, this wouln't have physical significance. The differentiable manifold together with the added structure of a particular pseudo-Riemannian metric nicely models some physics. Particular pseudo-Riemannian metric, because different pseudo-Riemannian metrics can be added to the same differentiable manifold, with very different results! For example, adding the Minkowski metric to \mathbb{R}^4 results in Minkowski spacetime. The same underlying differentiable manifold, yet one spacetime is singular and the other spacetime is non-singular!
TrickyDicky said:
I'm not sure what you mean here, but I'd say the metric(distance function) is never physically irrelevant in GR. One of the pillars of the theory is the invariance of length across arbitrarily long distances, think of cosmological redshifts. If we didn't care about metrics (distances) in GR there would be no need for a curvature concept or unique connections.
As the example of open FLRW universes demonstrates, the added pseudo-Riemannian metric is the physically significant structure that is added.
TrickyDicky said:
Why is the spacetime interval relevant in SR and not in GR?
The spacetime interval is very relevant physically. For example, consider an observer's worldline that joins events p and q. The worldline doesn't have to be a geodesic, as the observer could be in a rocket. How much observer wristwatch time elapses between p and q? Appropriately integrate the spacetime metric along the worldline to find out.
atyy said:
In cosmology, 4D spacetime is cut into 3D spatial slices that change with time. On the 4D spacetime, there is a pseudo-Riemannian metric tensor, and no physically relevant metric space metric. On each 3D spatial slice there is a Riemannian metric tensor, which can be used to define a metric space metric.
As another example, again consider FLRW universes. What is the present proper spatial distance between galaxies A and B? Appropriately integrate the spacetime metric along a path in the "now" spatial hypersurface to find out.
I think that this is a beautiful interplay between physics and mathematics.