How Does Theorem 4.5 Relate to P's and Q's?

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Homework Help Overview

The discussion revolves around the relationship between Theorem 4.5 and the concepts of p's and q's in the context of vector spaces and polynomial functions. The theorem involves arbitrary vectors, while the question pertains to specific polynomial forms.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore how Theorem 4.5 applies to the question regarding p's and q's, questioning the relevance of the theorem's variables. There is also a discussion on identifying the necessary steps to determine if the polynomials meet a specific condition related to the distributive property.

Discussion Status

The conversation includes attempts to clarify the theorem's application and the nature of the polynomials involved. Some participants provide guidance on testing the distributive property using examples, while others express uncertainty about the initial steps required for their analysis.

Contextual Notes

There is mention of P_2, which denotes the space of second-order polynomials, and the need for a third polynomial to test the distributive property, indicating a focus on polynomial functions within vector spaces.

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Homework Statement



Screenshot2012-07-19at24040AM.png


here is theorem 4.5

Screenshot2012-07-19at23441AM.png



The Attempt at a Solution



How can theorem 4.5 even relate to the question? The question deals with p's and q's and the theorem deals with u v w.
 
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The short version of what I said in the other thread is this:

The theorem deals with three arbitrary vectors that are elements of a given vector space. They do not need to be called u, v, and w.
 
well how do i even find out if
p(x) = a0 + a1x + a2x2
q(x) = b0 + b1x + b2x2 and P2
meets the condition (u+v) *w = u*w + v*w?
What's the first question I ask myself? I don't even know what step 1 is, much less 2 and 3
 
[itex]P_2[/itex] denotes the space of second-order polynomials. All you need to test this condition is to come up with a third "vector" (another second-order polynomial) that you can plug in as w.

This condition you're testing is the distributive property. It's the same thing as saying that (5+10)x6 = 5x6 + 10x6. I can plug in any three numbers there instead of 5, 10, and 6 and it works because the real line is a (very simple) vector space of sorts.

What you do to test this is simple. If I want to test the distributive property on real numbers, I go to what I just wrote and say, hm, is (5+10)x6 -> 15x6 really equal to 5x6 + 10x6?

At that point, you just evaluate both sides until you get something that's obviously (un)equal.
 
ok, i got it.
 

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