How Does Time-Reversal Invariance Affect Phi 4 Theory Renormalization?

Click For Summary
SUMMARY

The discussion focuses on the implications of time-reversal invariance on the renormalization of the Phi 4 theory, specifically examining the vacuum expectation value of the quartic interaction. The terms ##\phi_{+}## and ##\phi_{-}## are defined using integrals involving creation and annihilation operators, leading to the conclusion that the term ##\bra{\overrightarrow{P'}}\phi_{1-}\phi_{2-}\phi_{3+}\phi_{4+}\ket{\overrightarrow{P}}## diverges. It is established that this divergence is nullified by time-reversal invariance, as supported by J. Schwinger's research.

PREREQUISITES
  • Understanding of quantum field theory concepts, particularly Phi 4 theory.
  • Familiarity with time-reversal invariance in quantum mechanics.
  • Knowledge of vacuum expectation values in quantum field theory.
  • Proficiency in using creation and annihilation operators in calculations.
NEXT STEPS
  • Study J. Schwinger's papers on time-reversal invariance and its implications in quantum field theory.
  • Explore advanced topics in Phi 4 theory renormalization techniques.
  • Learn about the role of vacuum expectation values in particle physics.
  • Investigate the mathematical framework of creation and annihilation operators in quantum mechanics.
USEFUL FOR

Physicists, particularly those specializing in quantum field theory, theoretical physicists researching particle interactions, and graduate students studying advanced quantum mechanics concepts.

Diracobama2181
Messages
70
Reaction score
3
Homework Statement
Given the energy momentum tensor
##\hat{T}^{\mu \upsilon}## and a Lagrangian with potential ##V=\frac{1}{2}m\phi^2+\lambda\phi^4##,
the quantity ##\bra{\overrightarrow{P'}}T^{\mu v}\ket{\overrightarrow{P}}## should diverge.
How would I go about the 1 loop re-normalization procedure on this term?
Relevant Equations
##\hat{T}^{\mu \upsilon}=\partial^{\mu}\partial^{\upsilon}-g^{\mu \upsilon}L##
##L=\frac{1}{2}\partial_{\mu}\partial^{\mu}-\frac{1}{2}m\phi^2-\lambda\phi^4##
##\phi=\frac{d^3k}{2\omega_k (2\pi)^3}\int(\hat{a}(\overrightarrow{k})e^{-ikx}+\hat{a}^{\dagger}(\overrightarrow{k})e^{ikx}))##
Let ##\phi_{+}=\frac{d^3k}{2\omega_k (2\pi)^3}\int(\hat{a}^{\dagger}(\overrightarrow{k})e^{ikx})##
and ##\phi_{-}=\frac{d^3k}{2\omega_k (2\pi)^3}\int(\hat{a}(\overrightarrow{k})e^{-ikx})##.
Then ##\phi^4=\phi_{1}\phi_{2}\phi_{3}\phi_{4}=(\phi_{1+}+\phi_{1-})(\phi_{2+}+\phi_{2-} )(\phi_{3+}+\phi_{3-}) (\phi_{4+}+\phi_{4-})##
Looking only at the term ##\phi_{1-}\phi_{2-}\phi_{3+}\phi_{4+}##, we find
##\bra{\overrightarrow{P'}}\phi_{1-}\phi_{2-}\phi_{3+}\phi_{4+}\ket{\overrightarrow{P}}## diverges. Unsure where to go from here. Any resources would be helpful. Thank you.
 
Last edited:
Physics news on Phys.org
A:The quantity you are interested in is the vacuum expectation value of a quartic interaction. This quantity is zero by time-reversal invariance, see e.g. this paper by J. Schwinger.
 

Similar threads

Replies
2
Views
2K
Replies
11
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 1 ·
Replies
1
Views
7K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
2
Views
2K