How Does Trace Class Operator Q Relate to Norms in Hilbert Spaces?

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camillio
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Hello, I'm reading Gaussian measures on Hilbert spaces by S. Maniglia (available via google) and I have the following issue, regarding the proof.

He states in Lemma 1.1.4:
Let μ be a finite Borel measure on H. Then the following assertions are equivalent:
(1) [itex]\int_H |x|^2 \mu(dx) < \infty[/itex]
(2) There exists a positive, symmetric, trace class operator Q s.t. for [itex]x,y \in H[/itex]
[tex]<Qx, y> = \int_H <x,z><y,z> \mu(dz).[/tex]

If (2) holds, then [itex]Tr Q = \int_H |x|^2 \mu(dx)[/itex].
--------

The proof begins:
Spse (2) holds. Let [itex](e_n)_{n\in \mathbb{N}}[/itex] be an orthonormal basis of H. Then
[tex] \int_H |x|^2 \mu(dx) = \sum_{n=1}^\infty \int_H |<x, e_n>|^2 \mu(dx) = \sum_{n=1}^\infty <Qe_n, e_n> = Tr Q < \infty.[/tex]

What I have trouble with is the transitiono to the sum of [itex]<Qe_n, e_n>[/itex]. If I suppose, that [itex]x, e_n[/itex] may be complex, then I miss the adjoint part of the absolute value.

Most probably I miss some trivial notion, so any help will be appreciated.
 
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By definition, ##|z|^2 = z\overline{z} ##, so ## |<x, e_n>|^2 = <x, e_n>\overline{<x, e_n>} = <x, e_n><e_n, x> ##.
 
I know, but what then with the following?
[tex] <Qx, y> = \int_H <x,z> <y,z> \mu(dz)[/tex]

If I understand correctly,
[tex] <Qe_n, e_n> = \int <e_n, x> <e_n, x> \mu(dx) = \int <e_n, x>^2 \mu(dx)[/tex]
which doesn't coincide with abs. value for complex numbers.
 
Read the first paragraph in 1.1. H is a real Hilbert space.
 
Damn, you're right! I'm deeply sorry, my trivial fault :-(