How Does Wavelength Affect Intensity in Physics?

Thread starter frede89
Start date Nov 28, 2007

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SUMMARY

The discussion focuses on the relationship between wavelength and intensity in physics, specifically through the equation I(x) = dP/dx * 1/A, where I represents intensity, P is power, A is area, and x denotes wavelength (lambda). Participants clarify that intensity can be expressed as I = P/A, and they explore how this relationship evolves when considering wavelength. The correct formulation emphasizes the derivative of power with respect to wavelength, indicating a nuanced understanding of how intensity varies with changes in wavelength.

PREREQUISITES

Understanding of basic physics concepts, particularly intensity and power.
Familiarity with calculus, specifically derivatives.
Knowledge of the relationship between area and intensity in wave physics.
Basic grasp of wavelength and its significance in wave phenomena.

NEXT STEPS

Study the derivation of intensity formulas in wave mechanics.
Explore the implications of wavelength on energy distribution in electromagnetic waves.
Learn about the applications of intensity in optics and acoustics.
Investigate the role of area in determining intensity in various physical contexts.

USEFUL FOR

Students of physics, educators teaching wave mechanics, and anyone interested in the mathematical relationships governing wave intensity and wavelength.

Nov 28, 2007

frede89

Homework Statement

Why is

I(x)= dP/dx*1/A

Where x is the wavelength lambda. P the power, A the area and I the intensity.

The Attempt at a Solution

I=P/A is all i know..

Thanks in advance

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Nov 29, 2007

frede89

Can someone please tell me if this is the anwser:

I=P/A

I(x)=P/A (x)

I(x)= P/(x) * 1/A

I(x)= dP/dx * 1/A

The anwser must be something like this, right?