How Does Wavelength Affect Intensity in Physics?

  • Thread starter Thread starter frede89
  • Start date Start date
frede89
Messages
2
Reaction score
0

Homework Statement



Why is

I(x)= dP/dx*1/A

Where x is the wavelength lambda. P the power, A the area and I the intensity.


The Attempt at a Solution


I=P/A is all i know..

Thanks in advance
 
Physics news on Phys.org
Can someone please tell me if this is the anwser:

I=P/A

I(x)=P/A (x)

I(x)= P/(x) * 1/A

I(x)= dP/dx * 1/A

The anwser must be something like this, right?
 

Similar threads

Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
Replies
7
Views
1K
  • · Replies 22 ·
Replies
22
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
6
Views
3K