How far away is she from the centre of the earth?

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Homework Help Overview

The discussion revolves around two physics problems: one involving static friction and the other concerning gravitational force at a distance from the Earth's surface. The context includes analyzing forces acting on a giant salamander and determining the distance from the center of the Earth where the gravitational force is one-quarter of that experienced at the surface.

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Approaches and Questions Raised

  • Participants discuss the equilibrium of forces for the first problem and mention the universal gravitation equation for the second problem. There are requests for detailed steps and equations, indicating a desire for clarity in problem-solving approaches.

Discussion Status

Some participants have provided partial insights into the problems, with one suggesting the use of the universal gravitation equation. However, there is no consensus on the solutions, and multiple interpretations of the problems are being explored.

Contextual Notes

Participants are encouraged to show their attempts as per forum rules, and there are indications of varying levels of understanding among them. The original poster's request for full equations and steps highlights the need for detailed guidance.

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answer with full equations please and steps if you can thanks in advance


7. Shirley and Wilhelmine pin a giant salamander (50 kg) against a wall with a force of 1500 N so that it is suspended off the ground without slipping. Draw a free body diagram for this situation, write equations for net force, and determine the coefficient of static friction that allows them to do this.


AND


8. Maddie, floating in space at some distance above the earth’s surface, notices that the force of gravity she is experiencing from the Earth is one-quarter what she would feel at the surface of the earth. How far away is she from the centre of the earth, in terms of the earth’s radius? How far above the surface of the Earth is she, in terms of the earth’s radius? The radius of the Earth is 6.38 × 106 m, and the mass of the Earth is 5.98 × 1024 kg.
 
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I'll only answer for number 7 for I have no time right now.

Net F = 0
F(friction) = F(due to gravity) for it to be in Equilibrium
1500N*static_cooficient_of_friction = 50kg*9.81m/s^2
static_cooficient_of_friction = 0.327.
 
You really need to study, this are all questions I can retrieve instantly and I'm a noob.

Simply use the universal gravitation equation.

F = Gm1m2/r^2

m2 = m1/4

solve.
 
answer with full equations please and steps if you can thanks in advance

First step is show your attempt as per forum rules.
 

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