How far did the ball roll during the first 5 seconds of its motion?

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Homework Help Overview

The problem involves a ball rolling down a hill with uniform acceleration, starting from rest. The original poster seeks to determine the distance the ball rolled during the first 5 seconds of its motion, given that it traveled 150 meters during the second 5 seconds.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of acceleration and the application of kinematic equations. There is uncertainty about the correctness of the acceleration value obtained by the original poster and the subsequent steps to find the distance for the first 5 seconds.

Discussion Status

Some participants have offered guidance on how to approach the problem using kinematic equations, while others are questioning the assumptions made regarding the acceleration and the calculations performed. Multiple interpretations of the problem setup are being explored.

Contextual Notes

The original poster expresses confusion about their calculations and the method to find the distance for the first 5 seconds. There is an indication that the problem may involve specific constraints related to the uniform acceleration and the initial conditions of the motion.

mayeh
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pls. help --> acceleration

Homework Statement


a ball starts from rest and rolls down a hill with a uniform acceleration traveling 150m during the second 5.0s of its motion. How far did it roll during the first 5.0s of its motion:confused:

pls. help

Homework Equations




The Attempt at a Solution

 
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what have u tried so far so that we can help u?
 
i tried to get its acceleration and i got a 3m/s^2, but after that i don't know what to do, I'm not even sure if i got it right.
 
What you have to see first is that the distance traveled by the rolling ball in the next 5 seconds is nothing but the difference between the distance traveled by the ball in 10 seconds and the distance traveled in 5 seconds.

By the simple kinematic equation, we know that:

S=ut+(1/2)at^2

Since the initial velocity u is 0, the ut component of the equation goes and only (1/2)at^2 is left.So the distance traveled in the next 5 seconds is nothing but:

(1/2)a{(10^2)-(5^2)}=150

Solve for 'a'.(It wouldn't work out to 3m/s^2.)
Now, u know 'a' so substitute it in the equation (1/2)a.5^2 to get the answer!
 

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