1. The problem statement, all variables and given/known data A ball starts from rest and rolls down a hill with uniform acceleration, traveling 130m during the second 6.0s of its motion. How far did it roll during the first 6.0s of motion? 2. Relevant equations I guess: v=v(0)+at v^2=v(0)^2+2ay x=x(0)+v(0)t+0.5at^2 3. The attempt at a solution Okay, if I am not mistaken, then the distance travelled by the ball is proportional to the square of the time passed. d is proportional to t^2 I have tried so many answers already. I have tried setting the second six seconds to be twice the time and then the distance is one fourth of 130m. That was wrong. I tried setting the time to twelve seconds. I have tried dividing the distance by two. If I set the time to be six seconds and the distance to be 130 meters, then I don't have the initial velocity. If I set the initial velocity to equal zero and then the time to be six seconds, I don't have the distance. I tried making the time proportional to the square root of the distance. I only have one more attempt, and this question threw me off because it gave me info about the second six seconds and not the first six seconds. If it were to ask me "How far did it go in twice this time?" then I would be able to answer it. But I really cannot find this answer. I have tried 35 meters, 11 meters, 130 meters, 98 meters, 22 meters, 65 meters. Nope. I figure it must be less than 130 meters because the ball is accelerating down the incline and it would go faster every second because the velocity is increasing. Please help me. Please.