How Far Does a Rocket Travel in 10 Seconds at 3600mph?

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Homework Help Overview

The discussion revolves around a rocket's travel distance in 10 seconds while ascending at a speed of 3600 mph. The original poster presents the scenario but lacks a complete problem statement and relevant equations.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants question the relevance of equations and the completeness of the problem statement. There are attempts to convert speed into feet per second and calculate average acceleration based on the given speed and time.

Discussion Status

Some participants have provided calculations related to the rocket's speed and acceleration, while others emphasize the need for a complete problem statement and relevant equations. The discussion reflects a lack of consensus on the problem's details and assumptions.

Contextual Notes

There are indications of missing information and a requirement for the original problem statement to be fully included in the discussion. Participants express frustration over the incomplete format and lack of clarity in the original post.

Bill Raines
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Member advised to fill out the template, especially the attempt at solution, for all homework help requests.

Homework Statement


A rocket blast off. In 10.0 seconds it is at 10,000 ft, traveling at 3600mph, The rocket is going straight up

Homework Equations

The Attempt at a Solution

 
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four possible answer
5280 ft/s^2
528 ft/s^2
100 ft/s^2
200 ft/s^2
 
The homework format you ignored is not as much a suggestion as it is a forum requirement.

What equations do you think are relevant?

Where is your attempt?

Also, you should state the entire question and all relevant information exactly as it was given.
 
It looks like the rocket doesn't reach 3600mph until 10 seconds into the burn. In this case

3600 mile/hour x 5280 feet/mile x 1 hour/3600 seconds = 5280 feet/second

5280 feet/second
______________ = 528 ft/second^2
10 seconds
 
Bill Raines said:
It looks like the rocket doesn't reach 3600mph until 10 seconds into the burn. In this case

3600 mile/hour x 5280 feet/mile x 1 hour/3600 seconds = 5280 feet/second

5280 feet/second
______________ = 528 ft/second^2
10 seconds
On the assumption that you are asked to find the average acceleration, that looks right.
 
RedDelicious said:
...

Also, you should state the entire question and all relevant information exactly as it was given.
@Bill Raines ,
You are still ignoring this portion of @RedDelicious ' reply to you.

Include the entire problem statement in the text of your post, even if you have stated part of the problem statement in the title.
 
There is no acceleration. How far does the skydiver travel horizontally before pulling the cord?
 
Bill Raines said:
There is no acceleration. How far does the skydiver travel horizontally before pulling the cord?
What skydiver? Where is a skydiver mentioned in your original problem statement?

This thread is going nowhere fast, what with the lack of complete problem statement, relevant equations, and attempt at solution. I am locking this thread. If you wish to pursue the question please re-post it in a new thread, being sure to state the complete problem statement as given to you, any equations from your notes or text that you think might be relevant, and show what you've tried in the way of an attempt at solution.
 

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