• Support PF! Buy your school textbooks, materials and every day products Here!

How far does Sam land from the base of the cliff?

  • Thread starter xstetsonx
  • Start date
  • #1
78
0
Sam (60 kg) takes off (from rest) up a 50 m high, 10° frictionless slope on his jet-powered skis. The skis have a thrust of 200 N. He keeps his skis tilted at 10° after becoming airborne, as shown in Figure P6.43. How far does Sam land from the base of the cliff?

a=F/m


I used 50/sin10 to get the length of the slope-287.94m. Then i calculated the f on the slope. 200N-mgsin10. then i use that to divided by the mass which gives 1.63 for a. after that i go the final velocity before it jump off. then i have no idea wat to do next
 

Answers and Replies

  • #2
ideasrule
Homework Helper
2,266
0
How long does he stay airborne for? How far, horizontally, does he travel in that time? If you don't know, look at your equations for kinematics and projectile motion.
 
  • #3
78
0
i know i need to get the time from the y axis then calculate the distance on x axis. but i am not sure wat do i put for Vi in the y axis
 
  • #4
ideasrule
Homework Helper
2,266
0
I thought you already calculated the speed that Sam leaves the cliff at. Just do Vsin10 to find the vertical component of his speed and that's your Vi.
 
  • #5
78
0
I thought you already calculated the speed that Sam leaves the cliff at. Just do Vsin10 to find the vertical component of his speed and that's your Vi.
so t=-50=(30.6528sin10)t+.5(-9.8)t^2
t=3.78
then for the x axis
(30.6528cos10)3.78+.5(200/60)(3.78^2)
the acceleration on x axis is just 200/60 right
 
Last edited:

Related Threads on How far does Sam land from the base of the cliff?

Replies
2
Views
1K
Replies
5
Views
3K
Replies
13
Views
16K
Replies
5
Views
252
Replies
2
Views
1K
  • Last Post
Replies
10
Views
5K
Replies
3
Views
1K
Top