How Far Does the 40Kg Skater Move?

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SUMMARY

The discussion centers on a physics problem involving two skaters with masses of 65 kg and 40 kg, respectively, who are pulling themselves along a 10 m pole. The solution utilizes the formula for center of mass, specifically x_{com} = \frac{m2}{m1 + m2} d, resulting in the 40 kg skater moving 3.8 m towards the center while the 65 kg skater moves 6.2 m. The calculations confirm that the problem is straightforward, leading to a consensus that the solution is indeed correct.

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suspenc3
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Hi, I must be doing something wrong...because i found this question wayyyy too easy.

Two skaters, one with mass 65Kg and the other with mass 40Kg stand on the ice rink holding a pole 10 m long and a negligible mass. Starting from the ends of the pole, they pull themselves along the pole until they meet. How far does the 40Kg skater move?

[tex]\frac{m2}{m1+m2} d[/tex]

[tex]xcom=3.8m[/tex]

m2 travels : 10m - 3.8m

m2 travels 6.2m

Is it as easy as this?
 
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suspenc3 said:
Hi, I must be doing something wrong...because i found this question wayyyy too easy.
Two skaters, one with mass 65Kg and the other with mass 40Kg stand on the ice rink holding a pole 10 m long and a negligible mass. Starting from the ends of the pole, they pull themselves along the pole until they meet. How far does the 40Kg skater move?
[tex]\frac{m2}{m1+m2} d[/tex]
[tex]xcom=3.8m[/tex]
m2 travels : 10m - 3.8m
m2 travels 6.2m
Is it as easy as this?


Looks like it. Your other one was even easier :wink:
 
it just doesn't make sence...Our assignments are always difficult

weird...
 

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