How Far Does the Trooper Travel to Catch the Speeder?

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SUMMARY

The discussion focuses on a physics problem involving a state trooper and a speeder. The trooper accelerates at 5.0 m/s² for 10 seconds, covering a distance of 250 meters and reaching a final velocity of 50 m/s. Meanwhile, the speeder, traveling at a constant speed of 40 m/s, covers 400 meters in the same time frame. The trooper is 150 meters behind the speeder when she stops accelerating, and the challenge is to determine how far the trooper travels to catch the speeder after this point.

PREREQUISITES
  • Understanding of kinematic equations, specifically d=v1t+1/2at² and d=1/2at².
  • Knowledge of relative velocity concepts in physics.
  • Familiarity with acceleration and constant speed motion.
  • Ability to solve equations involving distance, speed, and time.
NEXT STEPS
  • Calculate the time it takes for the trooper to catch the speeder using relative velocity.
  • Explore advanced kinematic equations for motion with constant acceleration.
  • Study graphical representations of motion to visualize the problem.
  • Review examples of similar physics problems involving acceleration and relative motion.
USEFUL FOR

Students studying physics, particularly those focusing on kinematics and motion, as well as educators looking for examples of real-world applications of acceleration and relative velocity concepts.

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Homework Statement



A state trooper sets up a radar trap. A speeder passes the trooper and continues going at a constant speed of 40 m/s. The instant the speeder passes the trooper, the trooper accelerates at 5.0 m/s/s for 10 seconds and then continues at a constant speed. How far will the trooper travel before she catches up to the speeder?

Homework Equations



d=v1t+1/2at^2
d=1/2at^2

The Attempt at a Solution



I figured out the distance traveled for the first ten seconds by the police man to be 250 meters and his final velocity being 50 m/s. The speeder's distance in 10 seconds is 400 meters. Now I do not know how to find the distance that it takes for the cop to catch the speeder.
 
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So what is the relative distance between them at the moment the cop stops accelerating?
Then with their relative velocity, how long will it take the cop to cover that distance?
 
The distance between the two cars would be 150 meters apart. The problem is that I do not know how to find a formula to discover the rest of the distance covered
 

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