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- Thread starter rugbygirl
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A hockey puck moving along the +x axis at 0.5 m/s collides into another puck that is at rest. The pucks have equal mass. The first puck is deflected 37degrees below the +x axis and moves off at 0.36 m/s. Find the speed and direction of the second puck after the collision.

_______________speed: m/s

direction [please use positive for counterclockwise (above the +x axis) and negative for clockwise (below the +x axis)]:

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We want to try to help you understand your homework, not just do it for you. Please show any relevant formulas to your problem and the work you have done on it.

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Vy = 0 - (second bold)*(sin(angle))

Vx^2 + Vy^2 = Vf^2

Take sq rt of Vx^2 + Vy^2....... I keep getting .255

Part b

tan(angle) = Vy/Vx

do inverse tan in calculator..... this gives u the angle.... and it will be pos.

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