How far from the table does the block hit the floor?

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Homework Help Overview

The discussion revolves around two physics problems involving momentum and projectile motion. The first problem concerns a bullet colliding with a block of wood and determining how far the block travels horizontally before hitting the ground. The second problem involves the collision of two hockey pucks and requires finding the speed and direction of the second puck after the collision.

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Approaches and Questions Raised

  • Participants explore the principles of momentum and impulse in collisions, questioning the application of formulas related to horizontal and vertical motion. There is an emphasis on showing relevant work and formulas to aid understanding.

Discussion Status

Some participants have provided guidance on the importance of showing work and relevant formulas. Others are attempting to apply trigonometric functions to solve for angles and velocities in the second problem, indicating a collaborative effort to clarify the concepts involved.

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Participants are encouraged to demonstrate their understanding through the work they have done, suggesting that there may be specific homework guidelines or expectations regarding the presentation of solutions.

rugbygirl
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A 0.015-kg bullet traveling horizontally at 399.9 m/s strikes a 4.1-kg block of wood sitting at the edge of a table. The bullet is lodged into the wood. If the table height is 1.2 m, how far from the table does the block hit the floor?

________________________m
 
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Momentum/Impulse/Collision

A hockey puck moving along the +x axis at 0.5 m/s collides into another puck that is at rest. The pucks have equal mass. The first puck is deflected 37degrees below the +x axis and moves off at 0.36 m/s. Find the speed and direction of the second puck after the collision.

_______________speed: m/s


direction [please use positive for counterclockwise (above the +x axis) and negative for clockwise (below the +x axis)]:
 
Hey rugbygirl. Welcome to PF!

We want to try to help you understand your homework, not just do it for you. Please show any relevant formulas to your problem and the work you have done on it.
 
Vx = (first bold) - (second bold)*(cos(angle))
Vy = 0 - (second bold)*(sin(angle))
Vx^2 + Vy^2 = Vf^2
Take sq rt of Vx^2 + Vy^2... I keep getting .255

Part b
tan(angle) = Vy/Vx
do inverse tan in calculator... this gives u the angle... and it will be pos.
 

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