1. The problem statement, all variables and given/known data A club-axe consists of a symmetrical 11.0 kg stone attached to the end of a uniform 2.9 kg stick, as shown in the figure. The length of the handle is L1 = 93.0 cm and the length of the stone is L2 = 10.0 cm. How far is the center of mass from the handle end of the club-axe? 2. Relevant equations 3. The attempt at a solution[/b I'm not sure how to do this, I can up with 58.9cm on my own but most likely not the correct way, any help appreciated!