How Far Will a Block Slide on an Incline with Friction?

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SUMMARY

The discussion centers on calculating the distance a block will slide up an incline with friction after starting with an initial velocity of 7.3 m/s. The incline angle is 51.5 degrees, and the coefficient of kinetic friction is 0.1. Key equations include kinetic energy (KE = W = 1/2mv(final) - 1/2mv(initial)), force components (F = mg sinΘ and Fnormal = mg cosΘ), and the force of friction (F(f) = µ Fnormal). The problem highlights the importance of energy conservation and the need for a smooth transition from horizontal to inclined motion.

PREREQUISITES
  • Understanding of kinetic energy and work-energy principles
  • Knowledge of forces acting on an incline, including gravitational and frictional forces
  • Familiarity with trigonometric functions related to angles
  • Basic algebra for solving equations involving mass and acceleration
NEXT STEPS
  • Study the principles of energy conservation in mechanical systems
  • Learn how to apply Newton's laws of motion to inclined planes
  • Explore the effects of friction on motion and energy loss
  • Practice solving problems involving inclined planes with varying angles and friction coefficients
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators looking for problem-solving strategies related to inclined motion and friction.

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Homework Statement


A block is sliding with an initial velocity of 7.3 m/s along a frictionless horizontal surface when it then goes up an incline of 51.5 degrees that does have friction. If the kinetic friction coefficient is 0.1 then how far along the incline (hypotenuse) will the object travel before it stops?
7-p-044.gif


Θ = 51.5°
µ(k) = 0.1
v(initial) = 7.3 m/s
v(final) = 0 ...because the question asks at what point will it stop, meaning there is no more speed.
g = 9.81
d = ?
m = ?
a = ? ...i do not know if i even need acceleration
F = ?
W = ?

Homework Equations


KE = W = 1/2mv(final) - 1/2mv(initial)
F = mg
W = Fd
Force up ramp... F = mg sinΘ
Normal Force against ramp... Fnormal = mg cosΘ
Force of friction between block and ramp... F(f) = µ Fnormal

The Attempt at a Solution


Honestly i have no clue where to even begin, i am so lost on this problem :(
Also, my equations could be wrong. Could somebody please give me a detailed walkthrough on how to solve this?
 
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df102015 said:
Honestly i have no clue where to even begin, i am so lost on this problem :(
Also, my equations could be wrong. Could somebody please give me a detailed walkthrough on how to solve this?
Alas, we cannot do that; it's against forum rules. You'll need to make some attempt at a solution before help can be given.

That said, I suggest that you consider how energy is traded and lost along the block's path.
 
There is a flaw in this question. The way the diagram is drawn, the transition from horizontal to inclined motion is sudden, implying a non-conservative impact. But my guess is that you should suppose there is a small radius allowing for a smooth transition.
 

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