- #1

h7u9i

- 1

- 0

A 4.0 kg bundle starts up a 30° incline with 128 J of kinetic energy. How far will it slide up the plane if the coefficient of friction is 0.30?So, I began finding the Normal

N=W(y)=4cos30=3.46

Then found friction

f=uN

f=.3*3.46=1.04

So

E=E

K=Ug + Q

K=mgh + fd

K=mg(dsin30)+fd

128=4(9.8)(.5)d+(1.04)d

128=20.64d

d=6.2m

But the answer says 4.3m. What's wrong?

Thanks!

EDIT:

So I figured it out... N=4*9.8cos30. Duh.

N=W(y)=4cos30=3.46

Then found friction

f=uN

f=.3*3.46=1.04

So

E=E

K=Ug + Q

K=mgh + fd

K=mg(dsin30)+fd

128=4(9.8)(.5)d+(1.04)d

128=20.64d

d=6.2m

But the answer says 4.3m. What's wrong?

Thanks!

EDIT:

So I figured it out... N=4*9.8cos30. Duh.

Last edited: