How Far Will the Ice Cube Travel Up the Slope?

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Homework Help Overview

The problem involves an ice cube sliding up a frictionless slope after being released from a compressed spring. The scenario includes calculating the distance the ice cube travels up the slope based on energy conservation principles.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the conversion of spring potential energy to gravitational potential energy and the calculation of height versus distance along the slope. There is confusion regarding the correct interpretation of the question and the necessary calculations to find the distance along the slope.

Discussion Status

Some participants have identified a misunderstanding in the original approach regarding the calculation of distance along the slope instead of height. There is ongoing clarification about the angle of the slope and its implications for the calculations.

Contextual Notes

Participants are working under the assumption that the slope angle is 25 degrees, and there is a need to clarify the relationship between height and distance along the slope in the context of the problem.

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Question statement
A 55g ice cube can slide without friction up and down a 25∘slope. The ice cube is pressed against a spring at the bottom of the slope, compressing the spring 10cm . The spring constant is 25N/m. When the ice cube is released, what distance will it travel up the slope before reversing direction?

Relevant equations
PE_s = PE_g
PE_s = 1/2kx^2
PE_g = mgh

Attempt at a solution
Maximum height is when all energy is converted to gravitational potential energy (frictionless environment)

Thus,

PE_s = PE_g

1/2kx^2 = mgh

1/2(25N/m)(0.1m)^2 = (0.055kg)(9.8m/s^2)(h)

h = 0.23m or 23 cm
(Answer is asked for in cm)

Not sure what I am doing wrong here...
 
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You computing the height, not the distance along the slope.
 
I'm so silly. I need to learn to read questions further before answering something different.

Distance up slope would be
0.23(sin 35°) = 0.40m = 40cm

but that's not right!

How do I compute the distance up the slope?
 
Wasn't it a 25º slope?
 
Yes, it was... Thanks...

:nb)
 

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