How Fast and at What Angle Must a Daredevil Jump to Cross a Canyon?

[Dan66Stang]

Hey guys/girls, I would appreciate some help on a problem that I am having trouble with.

A daredevil jumps his motorcycle across a canyon. If his acceleration is 9.81 m/s^2 downward, determine:

a) the initial speed Vo required to complete the jump.
b) the final speed Vf.
c) The surface angle theta required at the end of the jump to ensure a smooth landing.

Okay here's some info about the jump.

Initial height = Ho = 70m
Final height = Hf = 35m
The canyon is 100m wide

Help would be appreciated, thanks.

 

[fizzzzzzzzzzzy]

what i would do is use x = x0 +vt + at^2 and plug in the appropriate numbers for both the x and y coordinates. and then for the angle you just plug in the x and y speeds for tangent and take that angle.

 

[Bitter]

Well, here are some hints. I would break this down into components. Find the motion in a horizontal motion then vertical, and then combine your vectors.

 

[hage567]

what i would do is use x = x0 +vt + at^2 and plug in the appropriate numbers for both the x and y coordinates. and then for the angle you just plug in the x and y speeds for tangent and take that angle.

This will not work for the x direction, since there is no acceleration in that direction when he is in the air.