How Fast Does a Dragster Accelerate?

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The discussion focuses on calculating the average acceleration of a dragster that accelerates from rest to 25 m/s in 0.61 seconds. The relevant kinematic equation is identified as v = v₀ + at, where v₀ is the initial velocity, v is the final velocity, and t is the time. Participants confirm the values for time and velocities, guiding towards the correct application of the equation. A link to HyperPhysics is provided for further clarification on acceleration definitions and equations. The conversation emphasizes the importance of understanding constant acceleration in solving the problem.
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A dragser and a driver together have a mass 905.5 the dragster, starting at rest, attains a speed of 25 m/s in .61s. find the average acceleration of the dragster during the time interval. answer in units of m/s.

ok I am assuming we have 3 variable for a kinematic equation t=.61s, v.=0, and v=25m/s so i would solve for acceleration using v=v.+at ... right? If not I need some help please.
 
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v=v.+at is correct, as is t=.61s, v.=0, and v=25m/s, which gives . . .

See the definition of acceleration here -

http://hyperphysics.phy-astr.gsu.edu/hbase/acca.html

Use the link "Motion equations when acceleration is constant" to see equations for 'constant' acceleration.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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