Kinematics Questions: Acceleration, Velocity, and the Speed of Light

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SUMMARY

This discussion focuses on kinematics, specifically the calculations of acceleration and velocity in various scenarios. The first question calculates the time required for an object accelerating at 9.8 m/s² to reach 10% of the speed of light, resulting in approximately 849.8 hours. The second question regarding an object's velocity before and after a specific time lacks clarity, as the time frame for "before" and "after" is not defined. The third question successfully computes the average acceleration of a dragster reaching 632 km/h in 3.72 seconds, yielding an acceleration of 47.2 m/s².

PREREQUISITES
  • Understanding of kinematic equations, specifically t = v/a
  • Knowledge of acceleration units (m/s²) and velocity units (m/s)
  • Familiarity with the concept of the speed of light (299,792,458 m/s)
  • Ability to convert units, such as km/h to m/s
NEXT STEPS
  • Study the derivation and application of kinematic equations in physics
  • Learn about relativistic effects when approaching the speed of light
  • Explore advanced acceleration calculations in different contexts, such as drag racing
  • Investigate the implications of uniform acceleration in real-world scenarios
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Students studying physics, educators teaching kinematics, and anyone interested in understanding motion dynamics and acceleration calculations.

Physicsrapper
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Hi, I have some questions regarding Kinematics:

1. If an object is accelerating at 9.8 m/s^2, how much time does it Need to reach ten percent of the Speed of light?

Speed of light: 299 792 458 m / s -> 10% -> 299 792 45,8 m / s

t = v/a -> 299 792 45,8 m / s / 9.8 m/s^2 = 3 059 106.714 s = 849.8 h


2. An object is uniformly accelerated at a = 4m/s^2. At time t, the object has a velocity v = 50 m/s. What is its velocity before and afterwards?

t = v/a = 50m/s / 4m/s^2 = 12.5 s

7.5s * 4m/s^2 = 30 m/s
17.5 s * 4m/s^2 = 70 m/s

3. The fastest dragster reaches 632 km/h in 3.72s. Find its average acceleration.

a=v/t -> 175.6m/s / 3.72s = 47.2m/s^2


Are all my Solutions true?
 
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Physicsrapper said:
Hi, I have some questions regarding Kinematics:

1. If an object is accelerating at 9.8 m/s^2, how much time does it Need to reach ten percent of the Speed of light?

Speed of light: 299 792 458 m / s -> 10% -> 299 792 45,8 m / s

t = v/a -> 299 792 45,8 m / s / 9.8 m/s^2 = 3 059 106.714 s = 849.8 h
Correct
Physicsrapper said:
2. An object is uniformly accelerated at a = 4m/s^2. At time t, the object has a velocity v = 50 m/s. What is its velocity before and afterwards?
This question does not make much sense to me. What do you mean by before? How many seconds before? Howmany seconds afterwards?
Physicsrapper said:
3. The fastest dragster reaches 632 km/h in 3.72s. Find its average acceleration.

a=v/t -> 175.6m/s / 3.72s = 47.2m/s^2
Correct
 
This question does not make much sense to me. What do you mean by before? How many seconds before? Howmany seconds afterwards?

Sorry, it's 5s.
Thank you for the correction!
 

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