How Fast is the Rocket Traveling According to Earth's Time Reference?

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Homework Help Overview

The problem involves a rocket traveling to a star located 27 light-years away from Earth, with a time dilation scenario where 12 hours pass on the rocket's clock. The objective is to determine the rocket's speed from Earth's reference frame, incorporating concepts of length contraction and time dilation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of time dilation and length contraction equations, questioning how to relate the time experienced on the rocket to Earth's time without knowing the rocket's velocity.

Discussion Status

Some participants have offered equations and methods for calculating the time in Earth's reference frame, while others express uncertainty about how to proceed without knowing the rocket's speed. There is an ongoing exploration of the implications of the speed limit set by the speed of light.

Contextual Notes

Participants note the assumption of no acceleration for the rocket and the challenge of working with incomplete information regarding the time experienced on Earth.

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Homework Statement


A star is 27c*y away from the rest reference of earth. A rocket reaches star A from Earth and according to clocks on it 12 hours have passed. How fast is the rocket traveling in Earth's reference frame?


Homework Equations


tpγ=t
Lp/γ=L


The Attempt at a Solution


The problem is under the category of length contraction and time dilation so I assume these are the two equations I must use. However when trying to do the problem I only was given t and Lp, and yet there are three variables (tp, L, and v). Help ;-(
 
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Can you calculate what time has passed wrt IRearth?
(I am assuming Earth is assumed to be an IR and the ship doesn't accelerate.)
 
yes, no acceleration.
I don't think I can calculate the time wrt IRearth..? I would need to know the velocity to do that so I knew the gamma factor correct?
 
vearth=dearth/tearth
tearth=dearth/vearth
plug and chug.
 
I don't know t_earth though? I only know it took 12 years from the spaceships frame..? oh... is Vearth 27c*y / 12 years...? I'm a noob X_X
 
but that's not REALLY the speed Earth see's it moving is it? Because Earth couldn't see the rocket traveling faster than C could it?
 
Enigman said:
vearth=dearth/tearth
tearth=dearth/vearth
plug and chug.

tearthγ=t
or, tearth=t/γ
equate the tearth
Quadratic eq in v2*earth
*editted
 
Last edited:

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