How Fast Must a Grasshopper Jump to Reach the Other End of a Straw?

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Discussion Overview

The discussion revolves around a physics problem involving a grasshopper jumping from a straw, focusing on the conditions under which the grasshopper can successfully reach the other end. Participants explore different jumping strategies, including jumping along the straw versus jumping sideways, and the implications of the grasshopper's mass relative to the straw's mass.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants propose that the smallest initial speed for the grasshopper to jump to the other end of the straw is achieved when jumping sideways, allowing the straw to rotate beneath it.
  • Others argue that jumping along the straw is a simpler approach, but acknowledge that the sideways jump introduces additional complexity with multiple coordinates.
  • One participant calculated an initial speed of ##v_0 = \sqrt{2lg}## but was challenged on the necessity of including the mass ratio ##m/M## in the solution.
  • There is a discussion about the conditions under which the grasshopper must jump sideways versus along the straw, with references to specific mass ratios influencing this decision.
  • Participants express uncertainty about the exact conditions needed for rotation versus translation of the straw during the jump.
  • One participant notes that for mass ratios ##m \ge 2M##, the grasshopper must jump sideways, while for ##m < 2M##, it should jump along the straw.
  • There is a question regarding whether the angle of the horizontal jump approaches 90° as the mass ratio approaches infinity.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the best approach to solve the problem, with multiple competing views on the jumping strategy and the influence of the mass ratio on the required speed.

Contextual Notes

Participants mention the need for specific angles and conditions related to the jump, as well as the moment of inertia of the straw, but do not resolve the mathematical steps or assumptions involved in the problem.

wrobel
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Recently I encountered a funny thing. Consider the following problem from high school course.

A small grasshopper of mass ##m## sits on a tip of a straw. The straw is a thin homogeneous rod of mass ##M## and of length ##2l##. The straw lies on a smooth horizontal floor.
What smallest initial speed must have the grasshopper to jump to other tip of the straw?

As a rule, people solve this problem assuming that the grasshopper jumps along the straw. Nevertheless, for some range of ##m/M## this is not true: the smallest speed is attained when the grasshopper jumps sideways from the straw and the straw rotates under him.

:)
 
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Jumping along the straw is nice and simple, but jumping to make the straw rotate brings in three coordinates that are all relevant. An interesting case.
 
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I got ##v0=\sqrt {2lg}##.

I felt compelled to solve it since I now teach at a high school.
 
osilmag said:
got v0=√2lgv0=\sqrt {2lg}.
Nope. The correct answer contains ##m,M## and for some range of ##m/M## it also contains nontrivial root of equation ## const\cdot\varphi=\sin\varphi##
 
LOL what?
 
Oh well, you didn't give an angle in your statement.
 
wrobel said:
the smallest speed is attained when the grasshopper jumps sideways from the straw and the straw rotates under him
Sure? If it can make the straw rotate, then it can make the straw slip underneath it, too, which shortens the necessary length of the jump.
 
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fresh_42 said:
Sure? If it can make the straw rotate, then it can make the straw slip underneath it, too, which shortens the necessary length of the jump.
Obviously. But the OP's point is that for some m/M values jumping non-parallel to the initial straw allows smaller speeds.
 
wrobel said:
2l2l2l. The straw lies on a smooth horizontal floor.
I assume this means friction-less?

wrobel said:
Nevertheless, for some range of m/Mm/Mm/M this is not true: the smallest speed is attained when the grasshopper jumps sideways from the straw and the straw rotates under him.
By "sideways" do you mean perpendicular to the straw, or at some non-zero angle? In either case the straw would rotate and translate.
 
  • #10
A.T. said:
Obviously. But the OP's point is that for some m/M values jumping non-parallel to the initial straw allows smaller speeds.
I'm not convinced, i.e. I do not see how the question can be solved on the given data. How much speed is needed for a rotation in comparison to a straight slip?
 
  • #11
fresh_42 said:
How much speed is needed for a rotation in comparison to a straight slip?
The OP states:
wrobel said:
The straw is a thin homogeneous rod
You can get the moment of inertial from that.
 
  • #12
A.T. said:
I assume this means friction-less?
yes
A.T. said:
do you mean perpendicular to the straw, or at some non-zero angle?
I mean some non-zero angle, this angle is a root of equation above
A.T. said:
You can get the moment of inertial from that.
exactly
I have not kept my draft, if I remember correctly, for ##m\ge 2M## the grasshopper must jump aside, if ##m<2M## he must jump along the straw
 
  • #13
A.T. said:
In either case the straw would rotate and translate.
yes it will rotate and translate
 
  • #14
wrobel said:
if I remember correctly, for m≥2M the grasshopper must jump aside,
Interesting. Do you remember if the horizontal jump angle approaches some value like 90° when m/M approaches infinity?
 
  • #15
pardon, ##\varphi## is an angle of straw's turn at the moment when the grasshopper landed on the tip.
I will restore my solution and put it here
 
  • #16
here it is
 

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