How Fast Should You Push the Box of Nails Down the Roof?

  • Thread starter Thread starter pdonovan
  • Start date Start date
  • Tags Tags
    Box Sliding
Click For Summary

Homework Help Overview

The problem involves determining the initial speed required to push a box of nails down a roof pitched at 25 degrees, considering the effects of kinetic friction. The context is rooted in physics, specifically in dynamics and kinematics.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to analyze the forces acting on the box using a free body diagram and applies kinematic equations to find the initial velocity needed. Some participants question the angle used in the calculations, suggesting a potential misunderstanding of the roof's pitch terminology.

Discussion Status

The discussion is exploring different interpretations of the roof pitch and its implications for the problem setup. Participants are providing guidance on the terminology and questioning the assumptions made regarding the angle of inclination.

Contextual Notes

There is a potential ambiguity regarding the definition of "pitch" in the context of the problem, which may affect the interpretation of the roof's angle. This has led to differing opinions on the correct angle to use in calculations.

pdonovan
Messages
17
Reaction score
0
Question:
You and your friend Peter are putting new shingles on a roof pitched at 25 . You're sitting on the very top of the roof when Peter, who is at the edge of the roof directly below you, 5.5 away, asks you for the box of nails. Rather than carry the 2.0 box of nails down to Peter, you decide to give the box a push and have it slide down to him. If the coefficient of kinetic friction between the box and the roof is 0.55, with what speed should you push the box to have it gently come to rest right at the edge of the roof?


My attempt:
I drew a free body diagram for the box while it is in motion. From there I concluded that:
Fnet = Fgsin20 - f
--> mgsin20 - .55N = ma
--> 2(9.8)sin20 - .55(2*9.8*cos20) = 2a
--> a = -1.7131

I then used the kinematics equations Vf = Vi + aT; and Sf = ViT + .5a(T^2) to find Vi = 4.34m/s.

Any help or guidance is greatly appreciated! Thank you.
 
Physics news on Phys.org
The method is fine, but the roof is inclined at 25 degrees to the horizontal, is not it? Why did you use 20 degrees?

ehild
 
Are we using the correct terminology for the roof slope in this problem? The pitch of a roof is the rise in a 12 inch run. A 12 pitch rises 12 inches and runs 12 inches for a 45 degree angle. A 25 pitch rises 25 inches in a 12 inch run for a slope of 64 degrees. When they use the term pitch in this problem do they mean the slope is 25 degrees or how a carpenter would use the term?
 

Similar threads

Replies
6
Views
5K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 4 ·
Replies
4
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
18K
Replies
3
Views
13K
Replies
1
Views
3K
Replies
13
Views
5K