# Nails going down the side of the roof

1. Feb 27, 2010

### charan1

1. The problem statement, all variables and given/known data
You and your friend Peter are putting new shingles on a roof pitched at 22 degree . You're sitting on the very top of the roof when Peter, who is at the edge of the roof directly below you, 5.0 m away, asks you for the box of nails. Rather than carry the 2.5 kg box of nails down to Peter, you decide to give the box a push and have it slide down to him.

If the coefficient of kinetic friction between the box and the roof is 0.53, with what speed should you push the box to have it gently come to rest right at the edge of the roof?

2. Relevant equations

Vf^2=Vi^2+2*a*delta s

F=ma

3. The attempt at a solution

First found the length of the roof by assuming that the height was 5m and angle 22* i found the length to be 13.3475meters using trig....sin(22)=5m/roof length

then i did the force calculations to find Fnet then find the acceleration:

9.8cos(22)*2.5kg=22.71N

9.8cos(22)*2.5kg*.53= -12.039N

Fnet=22.71-12.039N
Fnet=10.671N

Then solved for the acceleration:

F=ma

10.671N=2.5kg * a
a=4.2684m/s^2

then i plugged those values into this equation to find Vi

Vf^2=Vi^2+2*a*delta s

0=Vi^2 + 2 * (4.2684m/s^2) * (13.3475m)

Vi=10.67m/s

is this correct? thank you!

2. Feb 27, 2010

### shallgren

For the net force, you calculated both gravity's force and the frictional force using cosine. The force of gravity down the ramp should be sine.

3. Feb 28, 2010

### charan1

I did both with sin and cosin and they were both wrong need help someone please help!

4. Feb 28, 2010

### charan1

well i got 1.144856m/s^2 after getting the net force along the roofs axis to be 2.862N and found the Vi to be 5.53m/s and that is also incorrect is it suppose to be negative?

Im having a lot of trouble here...

5. Feb 28, 2010

### shallgren

Well the acceleration should be negative because the frictional force exceeds the force due to gravity.

Maybe your problem is in assuming "5 meters away" meant directly away from the one on top of the roof rather than down the roof.