How hard of a Hit force does it take to make a mass jump?

[MIKES279]

Guessing that you meant to write that a block is moving upward at 2.18 feet / sec^2, unimpeded by anything other than gravity.

The easy way to approach this from first principles is to start by computing how long it will take for the object to slow to a stop. That result can be obtained by $$t = \frac{v}{a}$$where $t$ is the time it takes, $v$ is the initial upward velocity and $a$ is the downward acceleration of gravity. In units of feet and seconds, the acceleration of gravity is approximately 32.2 feet per second squared.

Since the acceleration is uniform, the average velocity is the mean of the initial velocity and the final velocity. The final velocity is zero, so this simplifies to$$v_\text{avg}=\frac{v}{2}$$where $v_\text{avg}$ is our sought-after average velocity and $v$ is the given 2.18 feet per second^2.

The upward distance travelled will be the product of the two:$$h = v_\text{avg} t = \frac{v}{a} \frac{v}{2} = \frac{v^2}{2a}$$If we use a calculator we can calculate:

Elapsed time: 67 milliseconds.
Average velocity: 1.09 feet per second
Height gained: 0.737 feet = 0.885 inches

thats not in C or C++?

 

[jbriggs444]

thats not in C or C++?

Ideally, it would be in "number 2 pencil and a sheet of paper". However, all I have handy is this forum software that uses $\LaTeX$ and a Windows calculator.

 

[Drakkith]

thats not in C or C++?

Nothing here needs to be in a computer program. It's all simple formulas that can be done quickly with pen and paper and a calculator. If anything a spreadsheet program like Excel would be just fine if you're looking for some barebones automation. You certainly don't need to go with C or C++ unless you plan on writing a serious program or you're practicing your coding.