How High Does a Ball Go If Thrown Upwards at 40m/s?

[cyberhev]

Homework Statement

Height reached by a ball if it is thrown vertically upwards with an initial velocity of 40m/s

Homework Equations

Using V^2=u^2+2as

The Attempt at a Solution

I have been told to ignore air resistance and let g =9.8 m/s. Any help anyone?

 

[Defennder]

Well you have the correct equation. Just plug in all the variables and solve for the displacement s.

 

[m.e.t.a.]

Consider that the balls's velocity of 40 m/s is being sapped away by gravity at a rate of 9.8 m/s/s. How much time (t) will it take for v to be reduced to zero?

What will the ball's average velocity be over time period t? (Now you can solve for h.)

(Also: you probably just made a typo but note that g is an acceleration and as such takes the unit "m/s/s", normally written "m/s²". "m/s" is a unit of velocity, not acceleration.).

 

[cyberhev]

Thank you! Yes it was a typo! I am right that even if this question states initial velocity is 40m/s the actual value of u in this question is zero? Also my transposition of this equation works out to be V^2-u^2 divided by 2a=s?

 

[LowlyPion]

Yes the final velocity is 0 for that equation.

So for your equation:

0 = 40² +2*(-g)*x

(if +X is up, then g carries a - sign.)

If time is all you want then you have an easier path with

|V| = |g|*t

t = V/g