How High Does Block m1 Rise After an Elastic Collision with m2?

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SUMMARY

The problem involves two blocks, m1 (5.02 kg) and m2 (9.10 kg), on a frictionless track, where m1 is released from a height and collides elastically with m2, which is initially at rest. The collision is governed by the conservation of momentum and kinetic energy principles. The maximum height to which m1 rises after the collision can be calculated using these conservation laws, taking into account the repulsive magnetic forces that prevent direct contact between the blocks.

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Homework Statement


Two blocks are free to slide along a frictionless wooden track ABC as shown in Figure P9.20. The block of mass m1 = 5.02 kg is released from A. Protruding from its front end is the north pole of a strong magnet, repelling the north pole of an identical magnet embedded in the back end of the block of mass m2 = 9.10 kg, initially at rest. The two blocks never touch. Calculate the maximum height to which m1 rises after the elastic collision.

http://www.webassign.net/pse/p9-26.gif



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The Attempt at a Solution


I don't even know where to start on this problem
 
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Conservation laws ring a bell?
 
Don't over complicate the problem. There is no friction, so all energy is conserved within the system. Think of the relationship between potential and kinetic energy and how they are converted into each other. Also, since there is an elastic collision, you need to use some momentum equations. Keep in mind that momentum and kinetic energy are both conserved in elastic collisions.
 

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