How High Does the Elevator Meet the Coin in Torronto Tower?

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SUMMARY

The problem involves calculating the height at which a coin dropped from the top of the Toronto Tower meets an elevator traveling at 370 m/min. The distance traveled by the coin is expressed using the formula 1/2 * a * t^2, where 'a' is the acceleration due to gravity. To find the meeting point, one must derive expressions for the height of both the coin and the elevator over time and set them equal to solve for time 't'. This approach leads to determining the specific height at which the two objects meet.

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elevator of torronto tower...?

the elevators in the torronto tower travels at 370m/min from ground level to the top floor . suppose that when the elevator begins to rise from ground level a coin is dropped from the top floor down the elevator shaft. at what height does the elevator meet the coin?


give me a hint to how to start this question...
i know that the distance traveeld by coin is given by 1/2*a*t^2
but i can't seem think of any way to put it all together...
 
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Write down an expression for the height vs. time of the coin (you've already sort of done this).

Write down an expression for the height vs. time of the elevator.

When the two meet, their heights will be equal. Therefore, you should equate these two expressions and solve for the time, t, that satisfies this equation.
 

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