1. The problem statement, all variables and given/known data 45a) A watermelon with a mass of 2 kg falls out of a tree house that is 5.4 m above the ground. What is the speed of the watermelon just before it hits the ground. (this part i have solved) mass = 2kg Δd= 5.4m v=? v1^2 =v2^2+2gΔd v1^2=0+2gΔd =0+2(9.8)(5.4) v1^2=√105.84 v1^2=10.28 m/s Now on to the part i didnt quite get. 45b) A cantaloupe with a mass of 0.45kg falls out of the other side of the tree house. It hits a tree branch at a speed of 6.3 m/s. How high is the tree branch from the ground? 2. Relevant equations v1^2 =v2^2+2gΔd v1^2-v2^2/2g=Δd 3. The attempt at a solution 45b) v1=0m/s v2=6.3m/s mass = 0.45 kg v1^2-v2^2/2g=Δd v1^2-v2^2/2g=Δd 6.3^2-0/2g=Δd 6.3^2/2(9.8)=Δd 6.3^2/19.6=Δd 39.69/19.6=Δd 2.025m = Δd thats the height i got, if it is not correct, can someone show me how to get the right height? or better yet get the right height and i can analyze and figure out how you got the right height?