(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

45a)

A watermelon with a mass of 2 kg falls out of a tree house that is 5.4 m above the ground. What is the speed of the watermelon just before it hits the ground.

(this part i have solved)

mass = 2kg

Δd= 5.4m

v=?

v1^2 =v2^2+2gΔd

v1^2=0+2gΔd

=0+2(9.8)(5.4)

v1^2=√105.84

v1^2=10.28 m/s

Now on to the part i didnt quite get.

45b) A cantaloupe with a mass of 0.45kg falls out of the other side of the tree house. It hits a tree branch at a speed of 6.3 m/s. How high is the tree branch from the ground?

2. Relevant equations

v1^2 =v2^2+2gΔd

v1^2-v2^2/2g=Δd

3. The attempt at a solution

45b)

v1=0m/s

v2=6.3m/s

mass = 0.45 kg

v1^2-v2^2/2g=Δd

v1^2-v2^2/2g=Δd

6.3^2-0/2g=Δd

6.3^2/2(9.8)=Δd

6.3^2/19.6=Δd

39.69/19.6=Δd

2.025m = Δd

thats the height i got, if it is not correct, can someone show me how to get the right height? or better yet get the right height and i can analyze and figure out how you got the right height?

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# Homework Help: How high is the tree branch(conservation in energy/kinematics)

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