How High Was the 200kg Mass Dropped to Achieve 400J of Kinetic Energy?

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SUMMARY

The discussion focuses on calculating the height from which a 200kg mass must be dropped to achieve 400J of kinetic energy (KE). Using the equations for kinetic energy (KE = (1/2)mv^2) and gravitational potential energy (PEg = mgh), the relationship between potential energy and kinetic energy is established. By applying the conservation of energy principle, the height can be determined by rearranging the equations to solve for h. The final calculation reveals that the mass was dropped from a height of approximately 20.4 meters.

PREREQUISITES
  • Understanding of kinetic energy and gravitational potential energy equations
  • Basic knowledge of mass, gravity, and energy conservation principles
  • Familiarity with algebraic manipulation to solve equations
  • Concept of ignoring friction in energy calculations
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  • Study the conservation of energy in mechanical systems
  • Learn how to derive height from energy equations in physics
  • Explore the implications of friction in energy calculations
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Homework Statement



Just before striking the ground, a 200kg mass has 400J of KE. If friction can be ignored, from what heigh was it dropped

Homework Equations



KE = (1/2)mv^2
PEg = mgh

The Attempt at a Solution



I drew a mass of 200kg and I drew the normal force at the top as well as the force of gravity (mg) at the bottom. My force of gravity = 9.81 and I know the KE = 400J I don't know what equation to use in order to find my height.
 
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