How high will the piston rise if its temperature is increased?

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Homework Statement



[PLAIN]http://img101.imageshack.us/img101/7498/thermo.jpg

A cylinder is closed by a massless piston of cross sectional area A which is connected to a spring of constant k. With the spring relaxed, the cylinder is filled with a gas. The initial pressure, volume and temperature are Pi Vi and Ti. How high will the piston rise if its temperature is increased to a final value of Tf?

Homework Equations



The Attempt at a Solution



I tried to find Pf and Vf.

Pf = Pi + kx/A
Vf = Vi + Ax

I then wrote the universal gas law for Pf Tf and Vf but I doubt this is correct because the equation was crazy long and complicated.
 
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Nope, only letters. Are the expressions I wrote for Pf and Vf correct?
 
kagnaroos said:
...

I then wrote the universal gas law for Pf Tf and Vf but I doubt this is correct because the equation was crazy long and complicated.
You have written out the expression for the pressure as a function of x and volume as a function of x. All you have to do is relate that, using the ideal gas law, to the change in temperature.

AM
 
kagnaroos said:
Nope, only letters. Are the expressions I wrote for Pf and Vf correct?

I think they are correct. But the expression for x will be really ugly. Just go ahead.

ehild
 
That gives a quadratic equation:

kx2 + (PiA + kVf/A)x + nR(Ti-Tf) = 0

I highly doubt this is the correct answer because this is an old exam question and impossible to do in ~10 minutes.
 
Well, it is not quite correct, there should be Vi instead of Vf in your term kVf/A. And you should replace nR by piVi/Ti.

Then use the formula for the solution of quadratic equations and exclude the negative root. It takes less time than 20 s.

ehild