How Is Acceleration Calculated When a Bureau Starts Moving on a Rough Surface?

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grouchy
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Homework Statement



A bureau rests on a rough horizontal surface ( mk=0.40, ms=0.50). A constant horizontal force, just sufficient to start the bureau in motion, is then applied.The acceleration of the bureau is:

Homework Equations



F= ma

The Attempt at a Solution



The answer is 0.98 m/s^2 but I'm not sure why. I thought you would only use the kenetic friction since it just starts to move.
 
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how can you get the applied force using the coefficient of static friction?..Coefficient of static friction= Fs/Fn
 
pinkyjoshi65 said:
how can you get the applied force using the coefficient of static friction?..Coefficient of static friction= Fs/Fn

Fn=mg. Fs=0.5*mg. To start it moving the applied force must be equal to Fs.
 
ohk..I see..so grouchy's answer is right, although the method is not
 
ok, so you take the fs and subtract the fk? right?
 
Why the question marks? fs is the force pushing the cabinet - fk is the force acting against the push. Use the total force on the cabinet to compute it's acceleration.