How is acceleration in relativity measured?

  • Context: Graduate 
  • Thread starter Thread starter atta_bo-y
  • Start date Start date
  • Tags Tags
    Acceleration Relativity
Click For Summary
SUMMARY

The discussion centers on the measurement of acceleration in the context of relativity, specifically addressing the concept of absolute acceleration. Participants clarify that proper acceleration can be measured using accelerometers, and it remains constant across different frames of reference. The conversation also touches on the implications of acceleration near black holes and the relationship between proper and coordinate acceleration, emphasizing that while velocity is relative, acceleration can be considered absolute in certain contexts. Key terms include proper acceleration, coordinate acceleration, and gravitational field effects.

PREREQUISITES
  • Understanding of proper acceleration and coordinate acceleration
  • Familiarity with the principles of special relativity
  • Knowledge of gravitational fields and their effects on objects
  • Basic comprehension of black hole physics
NEXT STEPS
  • Research the concept of proper acceleration in detail
  • Study the effects of time dilation in special relativity
  • Explore the relativistic velocity addition formula
  • Investigate the behavior of objects near black holes and their escape velocities
USEFUL FOR

Students and professionals in physics, particularly those studying relativity, astrophysics, and gravitational effects, will benefit from this discussion.

atta_bo-y
Messages
5
Reaction score
0
Hey,

I'm new here. It's just very hard to find my specific question on the internet (at least I was not successful). Or maybe my question is just too obvious...

Ok here it goes:

I have two objects: A, B. A is accelerating relative to be. (-> B is accelerating relative to A)
Generally one can feel the effects of acceleration, right?
Now how do I know which one is "really" accelerating?? I know it sounds stupid... But somehow I just don't get it.

And yet another question on acceleration:

Black Holes: How come when you constantly accelerate, you can escape (or just not see) the photons in the horizon??
And with the "loss of entropy": Does that now mean that a random object in space has some "hot particles" around it, because it's accelerating to "some" other object??

Please help me here. I'm really confused.

regards atta_bo-y
 
Physics news on Phys.org
atta_bo-y said:
Generally one can feel the effects of acceleration, right?
Yes. In principle one can always detect acceleration.
Now how do I know which one is "really" accelerating??
Put an accelerometer in each frame and see which one registers the acceleration.
 
atta_bo-y said:
I have two objects: A, B. A is accelerating relative to be. (-> B is accelerating relative to A)
Generally one can feel the effects of acceleration, right?
Now how do I know which one is "really" accelerating?? I know it sounds stupid... But somehow I just don't get it.
Accelaration is absolute. We can measure the absolute acceleration of A without knowing how B is moving. If A is accelerating we can feel a "gravitational field" in its proper frame.
 
ghc said:
Accelaration is absolute. We can measure the absolute acceleration of A without knowing how B is moving. If A is accelerating we can feel a "gravitational field" in its proper frame.

Could you please define "absolute" for me? (It seems to have several distinct meanings.) Shouldn't at least be the magnitude of the acceleration relative?? Sorry, but I'm still confused.
 
The velocity is relative, that means we always need to precise the frame in which it is measured. The velocity of an object looks different if it is measured from different frames.
However, acceleration has always the same "value" independently from which frame it is measured including the proper frame of the accelerating object. So we can measure the acceleration of A from its proper frame.
 
ghc said:
The velocity is relative, that means we always need to precise the frame in which it is measured. The velocity of an object looks different if it is measured from different frames.
However, acceleration has always the same "value" independently from which frame it is measured including the proper frame of the accelerating object. So we can measure the acceleration of A from its proper frame.

Oh... I think I get that part now! Thank you so much ghc and Mentz114...

But that doesn't answer my other questions on black holes and entropy, does it??
 
ghc said:
The velocity is relative, that means we always need to precise the frame in which it is measured. The velocity of an object looks different if it is measured from different frames.
However, acceleration has always the same "value" independently from which frame it is measured including the proper frame of the accelerating object.
That's only true if you're talking about proper acceleration (which by definition is equal to the instantaneous coordinate acceleration in the inertial frame where the object is at rest at that moment), not the coordinate acceleration in an arbitrary inertial frame. For example, in the http://math.ucr.edu/home/baez/physics/Relativity/SR/rocket.html we see that although the proper acceleration is constant (which means an observer on the rocket will feel a constant G-force), the coordinate acceleration (derivative of coordinate velocity with respect to coordinate time) is continuously decreasing as the rocket approaches the speed of light in whatever inertial frame we're using to plot its motion. This is one way that SR differs from Newtonian mechanics, where acceleration does have the same value in every inertial frame.

On the other hand, it is true that the yes-or-no answer to whether an object is accelerating at a given point on its worldline is agreed upon by all inertial frames, so in this sense acceleration is absolute in SR.
 
Last edited by a moderator:
Proper Acceleration is -- What is provided by the force and Co-ordinate Acceleration is what is observed. Right?
 
Thank you JesseM!

Coordinate acceleration is the derivative of the coordinate velocity with respect to coordinate time. Proper acceleration is the coordinate acceleration as seen in the inertial frame where the object is at rest in the moment when the derivative is taken, right? And the proper acceleration is equal to the G-acceleration measured in the accelerating proper frame of the object, is that true?

Now if we take the example of a rocket that is keeping its proper acceleration constant, its coordinate acceleration calculated in an arbitrary inertial frame will be decreasing with time. This is due to the fact that each inertial frame used to define the proper accelaration of the rocket at one moment has a higher speed than all previous frames, and the time dilation keep growing from one frame to the next. As the proper acceleration is the same in all these frames, that make us see that the coordinate acceleration of the rocket is decreasing in our inertial frame. Is that true?
 
  • #10
thecritic said:
Proper Acceleration is -- What is provided by the force and Co-ordinate Acceleration is what is observed. Right?
Right.
ghc said:
Thank you JesseM!

Coordinate acceleration is the derivative of the coordinate velocity with respect to coordinate time. Proper acceleration is the coordinate acceleration as seen in the inertial frame where the object is at rest in the moment when the derivative is taken, right? And the proper acceleration is equal to the G-acceleration measured in the accelerating proper frame of the object, is that true?
Yup.
ghc said:
Now if we take the example of a rocket that is keeping its proper acceleration constant, its coordinate acceleration calculated in an arbitrary inertial frame will be decreasing with time. This is due to the fact that each inertial frame used to define the proper accelaration of the rocket at one moment has a higher speed than all previous frames, and the time dilation keep growing from one frame to the next.
I think a quantitative explanation would require more than just time dilation, but maybe it could be understood in terms of the relativistic velocity addition formula, since if you pick the rocket's instantaneous rest frame at some moment and then look at the increase in velocity dv in a short time after that moment dt as measured in that frame, the answer will be the same from one moment to the next, but from one moment to the next the velocity of the rocket's instantaneous rest frame is increasing in the frame of some fixed inertial observer.
 

Similar threads

  • · Replies 35 ·
2
Replies
35
Views
4K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 50 ·
2
Replies
50
Views
5K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K