How Is Electric Flux Calculated Through a Tilted Surface?

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SUMMARY

The electric flux through a tilted surface in a uniform electric field can be calculated using the formula flux = EAcos(theta). In this case, the surface measures 3.8 mm per side and is subjected to an electric field of 2000 N/C at an angle of 35° with respect to the normal. The calculated electric flux is -0.023657 N*m²/C, indicating that the field lines are entering the surface. This calculation confirms the correct application of the electric flux formula and the cosine of the angle between the field and the normal.

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[SOLVED] Flux through a surface

Homework Statement


The square surface shown in Figure 24-26 measures 3.8 mm on each side. It is immersed in a uniform electric field with magnitude |E| = 2000 N/C. The field lines make an angle of 35° with a normal to the surface, as shown. Take that normal to be directed "outward," as though the surface were one face of a box. Calculate the electric flux through the surface.

http://personalpages.tds.net/~locowise/test/24-26.gif

E=2000N/C
theta=(180-35)=145
A=(0.0038m)^2=1.444*10^-5 m^2


Homework Equations


flux=EAcos(theta)



The Attempt at a Solution


flux=2000N/C * (1.444*10^-5 m^2) cos145 = -0.023657 N*m^2/C
 
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Your answer is correct, and your work looks sound. Do you have any other questions?
 

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