How Is Energy Dissipated in a Capacitor and Resistor Circuit?

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Energy dissipation in a capacitor and resistor circuit involves understanding the voltage across the capacitor and the role of switches in the circuit. Initially, the capacitor charges when switch S1 is closed, but the voltage across it may not be 24V as assumed. The presence of the variable resistor affects the potential difference (pd) across the capacitor and the energy dissipated in the resistor. The time constant of the circuit is determined by the resistance and capacitance values. Accurate calculations require considering the specific configuration and resistance values in the circuit to determine the correct energy dissipation.
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Homework Statement


https://isaacphysics.org/api/images/content/questions/physics/circuits/capacitors/level4/figures/Circuits_potentiometer_capacitor_otp_2.svg
PQ is a slide-wire of uniform resistance, and J is a moveable contact at some point along it, such that the length from P to J is a known distance l. The total length of PQ is also known to be 1.00m. V=24.0V, C=10.0mF.
Find the energy dissipated. Given that initially S1 is closed and S2 is open, and l=326mm. The circuit is left in this arrangement for long enough that the circuit reaches a steady state. Then S2 is opened and S1 is closed simultaneously.

Homework Equations


E=0.5cv^2

The Attempt at a Solution


So using the above eqn i assumed that the pd across the capacitor will be 24v(because the same voltage flows through the variable resistor branch and the capacitor branch. Now as the current stablies there should be no current flowing through the capacitor. Hence the pd across the capacitor is 24v. Now the total energy of the capacitor = total energy dissipated by the resistor ) then i calculated the energy E=0.5*10*(10^-3)*24^2=2.88
Is this right baecause the answer is different
 
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Hashiramasenju said:
Find the energy dissipated. Given that
initially S is closed and S is open
Please include the subscripts on the switch labels; i.e., the S's.

Think a bit more about whether or not the pd across the capacitor is 24V initially.
 
What do you think is achieved by those switches? Nothing?
 
NascentOxygen said:
What do you think is achieved by those switches? Nothing?
S1 basically charges the capacitor but S2 helps discharge the capacitor and time constant =RC=R*10*10^-3
I have a doubt that the pd across the capacitor is not 24v.
Otherwise the energy dissipated in the resistor is not equal to the energy the capacitor posseses
 
Hashiramasenju said:
I have a doubt that the pd across the capacitor is not 24v.
PD across capacitor is never even close to 24v here. What is the function of the slider on the resistance wire?

Otherwise the energy dissipated in the resistor is not equal to the energy the capacitor posseses
Does the question ask for the energy dissipated in specifically resistor R?
 
NascentOxygen said:
PD across capacitor is never even close to 24v here. What is the function of the slider on the resistance wire?Does the question ask for the energy dissipated in specifically resistor R?
But shouldn't the voltage across a parallel circuit be the same regardless of the resistance?
 
Line PJQ is a slide resistor. So section PJ has significant resistance. Likewise for section JQ. Might be helpful if you included resistor symbols in these two sections.
 
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Thanks a lot got it
 
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