How Is Force Calculated in a Human Cannonball Act?

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The discussion centers on calculating the force exerted on John Tailor during his launch from a compressed-air cannon in the Bouglione circus in 1976. Given his mass of 70 kg and an exit velocity of 40 m/s from a 20 m long barrel, the force can be determined using Newton's second law, F = ma, where acceleration must first be calculated. The relevant equations of motion indicate that the initial velocity is 0 m/s, and the final velocity is 40 m/s over a distance of 20 m, which is crucial for finding the acceleration and subsequently the force.

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During the performance of the Bouglione circus in 1976, John Tailor was fired from a compressed-air cannon whose barrel was 20m long. Taylor emerged from the cannon at 40 m/s. If Tailor's mass was 70kg, find the force on him during the firing of the cannon.

I'm at a loss for what to do. I understand that in order to get the force I must get the acceleration first. What's the relevance of the length of the barrel to the computations? How should I proceed? Thank you! ^__^.
 
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Well, force F is just mass times acceleration, or F = ma. We know the mass, so we must find the acceleration.

Now all we have to do is think of the appropriate equation of motion to use.

We know he starts at rest so v0 = 0, he emerges from the cannon at v=40 m/s, and the distance over which he is accelerated is 20 m.

So, what equation do we use?

http://hyperphysics.phy-astr.gsu.edu/hbase/mot.html#mot1
 

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