How Is Lift Calculated Using the Bernoulli Principle for an Airplane Wing?

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SUMMARY

The lift generated by an airplane wing can be calculated using the Bernoulli Principle, specifically through the equation P1 + (1/2)ρV1² = P2 + (1/2)ρV2². In this discussion, the air density is established at 1.29 kg/m³, with airflow speeds of 347 m/s over the top surface and 289 m/s over the bottom surface. The resulting pressure difference is calculated to be 5.39 x 10^4 N/m², leading to a total lift force of 4.6 x 10^6 N when applied to a wing area of 84.5 m². The calculations confirm the validity of the Bernoulli equation in determining lift.

PREREQUISITES
  • Understanding of the Bernoulli Principle
  • Knowledge of fluid dynamics
  • Familiarity with pressure and lift force equations
  • Basic proficiency in algebra and unit conversions
NEXT STEPS
  • Study the application of the Bernoulli Principle in various aerodynamic scenarios
  • Learn about the effects of wing shape and angle of attack on lift
  • Explore computational fluid dynamics (CFD) tools for simulating airflow
  • Investigate the relationship between lift and drag in aviation
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Aerospace engineers, physics students, and anyone interested in understanding the principles of lift generation in aviation.

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Homework Statement



Find the lift in Newtons due to the Bernoulli Principle on a wing of a plane of area 84.5 m^2 if the air passes over the top and the bottom surfaces at speeds of 347m/s and 289 m/s


Homework Equations



P1+(1/2)densityV^2 =P2+(1/2)densityV^2

The Attempt at a Solution



Ok so i know the density of air is 1.29kg/m^3

so i plug into equation to get

1/2(1.29kg/m^3)(347m/s)^2= 1/2(1.29kg/m^3)(289m/s)^2

then i get answer of 5.39x10^4 N/m^2

then i use equation F=PA

and P is 5.39x10^4 N/m^2 and A is 84.5m^2

to get answer of 4.6x10^6 N

Am i correct ?
 
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By bernouili equation
Pa+1/2pva^2 = Pb =1/2pvb^2
1/2pvb^2-1/2pva^2 =Pa-Pb
deltaP = 1/2pvb^2-1/2pva^2
deltaP * A =Lift force
I think your method is correct
 

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