How is momentum conserved in a Gauss Gun?

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SUMMARY

The discussion centers on the conservation of momentum in a Gauss Gun setup, where a steel ball is propelled by magnets. Participants clarify that while momentum is typically conserved in isolated systems, in this case, energy is drawn from the magnetic configuration to accelerate the balls, resulting in a net loss of momentum. The confusion arises from the distinction between momentum and energy conservation, as the system requires mechanical work to reset the balls. The key takeaway is that momentum is not conserved in this specific Gauss Gun configuration due to external energy input.

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  • Understanding of basic physics concepts, particularly momentum and energy conservation.
  • Familiarity with the mechanics of a Gauss Gun and its operational principles.
  • Knowledge of kinetic energy and its relationship to momentum.
  • Ability to perform calculations involving mass and velocity.
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Physics students, educators, and hobbyists interested in understanding the mechanics of Gauss Guns and the principles of momentum and energy conservation in dynamic systems.

adrianowatson
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Homework Statement


So for those who aren't familiar with the Gauss Gun here is a video demonstrating its function:

As you can see in the video, a steel ball is rolled towards a sequence of magnets and other steel balls and as the incoming ball strikes the magnet, the ball on the other end ejects at a higher velocity. NOTE: in the video there is recoil but in my case there isn't recoil as the magnet is stuck in place.

Homework Equations


Momentum is calculated by mass*velocity.

The Attempt at a Solution


But this doesn't make sense to me as both the incoming and outgoing steel balls have the same mass but they travel at different velocities so when momentum is calculated, isn't the momentum different and means that momentum isn't conserved in this system?

Please clarify this for me as I've been struggling with this concept for quite a while and can't get my head around it. I would also like to have an equation for showing the conservation of momentum for multiple variations of this setup.

Thanks in advance
 
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Hello Adriano, :welcome:

Did you read some of the explanations ? Anything unclear :smile: ?
 
BvU said:
Hello Adriano, :welcome:

Did you read some of the explanations ? Anything unclear :smile: ?

Hi, I've come across this website before and just gives explanations to do with Kinetic Energy and not momentum. I'm specifically asking how momentum is conserved in this system.

Thanks!
 
Momentum is not conserved: energy is drawn from the magnetic configuration and used to accelerate the balls (just before they bump into the magnet).

Look at it this way:
To reload, you must do mechanical work: exercise force to peel the sticking balls back from the magnets. To peel it off is more work than you get back when it ckicks onto the preceding ball again (becasue it's further from the magnet by 1 ball diameter). That's exactly what the link tells you.
 
BvU said:
Momentum is not conserved: energy is drawn from the magnetic configuration and used to accelerate the balls (just before they bump into the magnet).

Look at it this way:
To reload, you must do mechanical work: exercise force to peel the sticking balls back from the magnets. To peel it off is more work than you get back when it ckicks onto the preceding ball again (becasue it's further from the magnet by 1 ball diameter). That's exactly what the link tells you.

Oh right I see, so momentum isn't conserved in this system?

I've looked at many other websites on this and some say momentum is conserved so I'm quite confused.
 
I stand corrected... (had looked at the next video where the magnets were 'fixed' in place and never gave it a second thought). o:)
 

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