How Is Normal Force Calculated on an Inclined Plane?

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SUMMARY

The minimum normal force required to prevent a 3.00 kg crate from sliding down a 35° incline with a static friction coefficient (μs) of 0.300 is calculated to be 32.1 N. This force is essential to increase the frictional force, which must counteract the gravitational component acting down the slope. The relationship between the normal force and friction is defined by the equation μs = Fk / n, where Fk is the frictional force and n is the normal force.

PREREQUISITES
  • Understanding of static friction and its coefficient (μs)
  • Basic knowledge of forces acting on an inclined plane
  • Familiarity with Newton's laws of motion
  • Ability to perform trigonometric calculations involving angles
NEXT STEPS
  • Study the derivation of forces on inclined planes in physics textbooks
  • Learn about the calculation of frictional forces in different scenarios
  • Explore the effects of varying angles on normal force and friction
  • Investigate applications of normal force in engineering contexts
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators teaching concepts related to forces on inclined planes.

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Homework Statement


μs = .300
Mass = 3.00kg
Incline = 35°
What is the minimum normal force applied to prevent the crate from sliding down the incline?

Homework Equations


μs = Fk / n


The Attempt at a Solution


The book solution is 32.1N but I have no idea how they got that.
 
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sakebu said:

Homework Statement


μs = .300
Mass = 3.00kg
Incline = 35°
What is the minimum normal force applied to prevent the crate from sliding down the incline?

Homework Equations


μs = Fk / n


The Attempt at a Solution


The book solution is 32.1N but I have no idea how they got that.

If this crate is left alone, it will slip down as friction is not big enough.

One way to stop it would be to apply an appropriate force parallel to the slope.

What is planned here is to apply a force perpendicular to the slope, which will increase the friction force so that it is strong enough to prevent motion.
 

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