How Is Normal Strain Derived in Continuum Mechanics?

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SUMMARY

The derivation of normal strain in continuum mechanics involves the Taylor expansion of the square root function, specifically sqrt(1+e), where "e" represents the small strain. The equation length(ab) ≈ dx + ∂u/∂x*dx is reached by assuming that the squares of the gradients are negligible and applying the approximation sqrt(1+e) ≈ 1 + e/2. This simplification is crucial for understanding how small deformations affect material behavior under stress.

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  • Understanding of continuum mechanics principles
  • Familiarity with Taylor series expansions
  • Knowledge of strain and deformation concepts
  • Basic calculus, particularly differentiation
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What are the mathematical steps and assumptions to reach the conclusion that length(ab) ≈ dx + ∂u/∂x*dx ?

If you consider the the squares of the gradients to be negligible, you still have a square root and multiplication by the constant "2". What other assumptions do we make to derive the final equation?
 
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You make a Taylor expansion of sqrt(1+e), where "e" is regarded to be small.
Then, you have, approximately, sqrt(1+e)=1+e/2.
 

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