- #1
mPlummers
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I know that, for charge conjugation, ##C_{\Phi} = -1##, ##C_{K^{+}} = 0##, ##C_{K^{-}} = 0##, but ##C_{\Phi} \neq C_{K^{+}}C_{K^{-}}##. How ##C_{tot}## is conserved in this interaction?
Does it mean i can't check for charge conjugation conservation in this process?
The decay ##\Phi \rightarrow K^{+}K^{-}## is possible because of the conservation of energy and momentum. The energy and momentum of the initial particle, ##\Phi##, is transferred to the final state particles, ##K^{+}## and ##K^{-}##, in accordance with the laws of physics.
The weak force is responsible for the decay of the initial particle, ##\Phi##, into the final state particles, ##K^{+}## and ##K^{-}##. This force is one of the four fundamental forces of nature and is involved in many nuclear and particle processes.
No, the decay ##\Phi \rightarrow K^{+}K^{-}## does not violate any conservation laws. It conserves energy, momentum, and charge, which are all important quantities in particle physics. The decay process follows the rules of the Standard Model, which is a well-tested theory that describes the fundamental particles and their interactions.
The branching ratio of ##\Phi \rightarrow K^{+}K^{-}## decay is determined through experiments. Scientists study large numbers of ##\Phi## particles and measure how many of them decay into ##K^{+}## and ##K^{-}## particles. By comparing this number to the total number of ##\Phi## particles, they can calculate the branching ratio.
Yes, the ##\Phi## particle can also decay into other combinations of particles, such as ##\pi^{+}\pi^{-}## and ##\rho^{+}\rho^{-}##. The decay mode of a particle depends on its properties, such as its mass and charge, and the available energy for the decay process.