How Is Tension Calculated in an Acrobat's Wire?

[jfri14]

Homework Statement

An acrobat hangs by his hands from the middle of a tightly strestched horizontal wire so that the angle between the wire and the horizontal is 9.15 degrees. If the acrobat's mass is 88.4kg, what is the tension in the wire? Answer in units of N.

Homework Equations

Sum of Fy =0
Sum of Fx =0
F= sqrt(Fx^2 + Fy^2)

The Attempt at a Solution

Fysin(9.15)-(88.4kg)(9.8m/s2)=0
Fy=5447.879N

Fxcos(9.15)-(88.4kg)(9.8m/s2)=0
Fx=877.486N

F= Sqrt(5447.879^2+ 877.486^2)
F=5518.0945N

 

[fliinghier]

draw a free body diagram and add the forces as vectors.