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How is the algebra of quaternions isomorphic to the algebra of matrices?

  1. Jul 23, 2012 #1
    I just started learning about morphisms and I came across a problem that totally stumps me. Here goes:

    Show that the algebra of quaternions is isomorphic to the algebra of matrices of the form:

    \begin{pmatrix}
    \alpha & \beta \\
    -\bar{\beta} & \bar{\alpha} \end{pmatrix}

    where α,β[itex]\in[/itex]ℂ and the overbar indicates complex conjugation.

    [Hint: If q=a+bi+cj+dk is a quaternion, identify it with the matrix whose entries are [itex]\alpha[/itex] =a+bi, [itex]\beta[/itex] =c+di, [itex]\bar{\alpha}[/itex] =a-bi, -[itex]\bar{\beta}[/itex] =-c+di, (a,b,c,d) [itex]\in[/itex]ℝ, i[itex]^{2}[/itex]=j[itex]^{2}[/itex]=k[itex]^{2}[/itex]=-1]

    Thanks a lot everyone!
     
  2. jcsd
  3. Jul 23, 2012 #2

    What have you tried? Have you already summed (multiplied) two of the above matrices and verified the sum behaves as the

    sum (product) of the respective quaternions?

    For example, heeding to the hint given, we'd have the identifications

    [tex]i \sim \begin{pmatrix}1&0\\0&-1\end{pmatrix}\,\,,\,j \sim \begin{pmatrix}0&1\\-1&0\end{pmatrix}\,\,,\,k \sim \begin{pmatrix}0&1\\1&0\end{pmatrix}[/tex]so do we have

    [tex]ij=k \sim \begin{pmatrix}1&0\\0&-1\end{pmatrix} \begin{pmatrix}0&1\\-1&0\end{pmatrix}\stackrel{?}=\begin{pmatrix}0&1\\1&0\end{pmatrix}\,\,??[/tex]

    DonAntonio
     
  4. Jul 23, 2012 #3
    Okay, I have verified that ij=k but I don't see what to do next.
     
  5. Jul 23, 2012 #4
    The more I look at this problem the less I understand what I am supposed to be doing. Without giving me any answers what I need is for someone to walk me through the steps to the solution. I need an understanding of what I'm trying to solve here.
     
  6. Jul 23, 2012 #5

    Ray Vickson

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    What does it MEAN for two algebraic structures to be isomorphic? (That is, there is a formal definition of isomorphism, and I am asking you what that is.) Then you need to show that all the parts of the definition hold true.

    RGV
     
  7. Jul 23, 2012 #6
    Okay, so an isomorphism is a bijectivity from one structure to another which preserves the characteristics of the structures. So if quaternions possess addition, scalar and quaternion multiplication I must show that this structure is isomorphic to the addition, scalar, and matrix multiplication of matrix algebra?
     
  8. Jul 23, 2012 #7

    Ray Vickson

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    Well, what do YOU think?

    RGV
     
  9. Jul 24, 2012 #8
    You know, I think that's pretty much what I am being asked to show. I appreciate your insights! So basically (and please excuse the poor notation, I'm on my phone):

    (H,\otimes,°,\oplus, =)~(M, ×, •, +, =)
     
  10. Jul 24, 2012 #9

    Ray Vickson

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    I guess so, depending on exactly what the symbols mean; anyway, if q1 ⇔ A1 and q2 ⇔ A2, you need q1+q2 ⇔ A1+A2, q1*q2 ⇔ A1.A2 (matrix product) and, for scalar c, cq1 ⇔ cA1, etc.

    RGV
     
  11. Jul 25, 2012 #10
    Wow, it isn't wizard math after all. Thanks man!
     
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