How is the area under the arch of y=sinx related to the unit circle?

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Homework Help Overview

The discussion revolves around the relationship between the area under the curve of the function y=sin(x) and the unit circle, as part of a year 12 mathematics investigation. The original poster is exploring geometric interpretations and calculations related to this area.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster considers using triangles and the relationship to the unit circle to determine the area under the sine curve. They present calculations for the areas of triangles and trapeziums and express confusion about the connection to a specific formula related to the area.

Discussion Status

Participants are encouraging the original poster to show their attempts at solving the problem, indicating that there are hints in the provided diagrams. The conversation is focused on clarifying the original poster's reasoning and calculations, with no consensus reached yet.

Contextual Notes

There is an emphasis on the requirement for the original poster to demonstrate their attempts before receiving help. The original poster expresses uncertainty about the derivation of a specific formula and the appropriateness of their calculations related to the area under the sine curve.

Trav44
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Hi guys I'm new to the forum but with year 12 maths coming up next year I assume I'll be coming here a lot.

This question is part of my end of year investigation.

I have scanned the questions and attached them as jpegs.

I was thinking something along the lines of using the triangle to determine the area? Or if the fact that this curve is related to half of a unit circle had something to do with it?

Any help would be much appreciated :)

Thank you, Travis
 

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You've got to show an attempt at solving the problem in order to get some help.
 
Hi Trav, welcome to the forums. I do hope you'll be coming here - and learning - a lot.
As SteamKing said, please show us your attempt or problem. The questions are leading you in a specific direction. As you've noticed, there is a pretty big hint in the picture in the form of the auxiliary lines that have been drawn, creating for example a triangle. If you show us how far you got with that, we may be able to help you complete it.
 
Sorry I was unaware that an attempt must be shown, I will be sure to include them in every question from here on out :)
My attempts for each question as follows are:
1. The area of the outer rectangle is pi as pi x 1 = pi
The area for the inner triangle is 1/2bh so 1/2 x pi x 1= 1/2pi or pi/2
this shows that the area under the sine arch must fit the range of pi./2 < x < pi

2.
Triangle area= 1/2 x b x h
1/2 x pi/4 x sin(pi/4)= 0.2776

Trapezium area = (a + b)/2 x h
(sin (pi/4) + sin(pi/2))/2 x pi/4=0.6704

total area = 0.2776x2 + 0.6704x2= 1.896

which is the correct area

I get that sin of (pi/4 or pi/2) is the height at those given points but could someone please give me an explanation as to why this is?

I have found the area for both triangles and trapeziums and multiplied them by 2 to give me the overall area and this is right how ever I cannot make the connection between this and the equation pi/4(1+(root 2))3. I can use the formula to add up all the areas and I get an answer close to 2 which seems logical as the area under a sine curve is meant to equal 2.
I do not understand how this formula has been derived though?
And for pi to be split into increments of 0.1 I thought the start of the equation should be 1/31.4 as this is pi/0.1?
1/20 would give increments close to 0.15 wouldn't it?
 

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