How is the Bragg condition satisfied for AOMs in a double pass configuration?

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SUMMARY

The discussion focuses on the Bragg condition in Acousto-Optic Modulators (AOMs) used in a double pass configuration. The key point is that during the first pass, the frequency of the incoming beam shifts from ω to ω+Ω at an angle θB. In the second pass, despite the frequency change, the Bragg condition remains satisfied because Ω is significantly smaller than ω, allowing θB to remain effectively unchanged for both frequencies.

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Niles
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Hi

I have a question on AOMs used in a double pass configuration. I understand the motivation for such a setup, but what I don't quite understand is the following: During the first pass, the frequency of the incoming beam is changed from ω to ω+Ω at an angle θB. Then we send the diffracted beam with frequency ω+Ω through the AOM once again at the same angle θB. This last part I don't quite undertand: How can the Bragg condition be satisfied for the angle θB at both ω and ω+Ω?


Niles.
 
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I think the idea is that in general Ω << ω, so the correct angle is essentially the same for the second pass as for the first.
 
Ah, I see. I thought it was most likely something like that, but I was worried that I had misunderstood something. Thanks for taking the time to reply.Niles.
 

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