How Is the Horizontal Distance Calculated When a Stone Drops on a Moving Log?

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Homework Help Overview

The discussion revolves around calculating the horizontal distance a stone travels when dropped from a height of 75 meters onto a moving log that travels at a constant speed of 50 meters per second. Participants are examining the relationship between the stone's fall and the log's movement.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Some participants question the correctness of the provided answer of 20 meters, suggesting it may be too low given the log's speed. Others propose using the displacement equation to find the time of fall and subsequently calculate the distance traveled by the log during that time.

Discussion Status

There is an active exploration of different interpretations of the problem, with some participants expressing doubt about the initial answer and suggesting that the calculations may lead to a different result. Guidance has been offered regarding the use of kinematic equations to analyze the situation.

Contextual Notes

Participants note potential errors in the question or the values provided, indicating that the assumptions made about the log's speed and the height from which the stone is dropped may need to be reconsidered.

eureka360
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hi guys.. could you please explain why 2.0x10^1 meters is the answer of the horizontal distance between the log and the bridge when the stone is dropped from rest from a 75-m-high bridge and lands on the log as it passess under the bridge if the log moves with a constant speed of 50 meters per second?
 
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Are you sure the answer is 20 meters? Its either ur answer is wrong or that the log is travellin at a speed too fast in water!
 
Last edited:
eureka360 said:
hi guys.. could you please explain why 2.0x10^1 meters is the answer of the horizontal distance between the log and the bridge when the stone is dropped from rest from a 75-m-high bridge and lands on the log as it passess under the bridge if the log moves with a constant speed of 50 meters per second?

Doesn't sound right. From the equation of the displacement of the stone y = 75 - \frac{1}{2}gt^2 you can obtain the time it takes to fall down, by setting y equal to zero and solving for t. Further on, use that time to obtain the distance of the log at the moment just before the stone is dropped.
 
well. The answer should be approximately 200 if the values given are correct. Or else, there may be some error in the question.
 
gunblaze said:
well. The answer should be approximately 200 if the values given are correct. Or else, there may be some error in the question.

Yes, it's near 200 [m].
 
the log is traveling 50 meters per second.. yeah i think its 200 meters..ok.. i got it.. thanks guys...
 

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