Horizontal Distance Between Log & Bridge | Homework Statement

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Homework Help Overview

The problem involves a log floating on water and a stone dropped from a bridge. The scenario includes calculating the horizontal distance between the log and the bridge at the moment the stone is released, given the height of the bridge and the speed of the log.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss how to determine the time it takes for the stone to fall 75 meters and how that relates to the log's horizontal movement. There are questions about the necessary equations and how to find time without initial velocity or acceleration details.

Discussion Status

Some participants have suggested starting with the time of fall and relating it to the log's motion. Others have attempted calculations based on the height and gravity, leading to a time estimate, but further clarification on the next steps is still needed.

Contextual Notes

Participants express uncertainty about the relationship between the stone's fall and the log's horizontal movement, indicating a need for more information or clarification on the physics involved.

noaamari
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Homework Statement



A log is floating on swiftly moving water. A stone is dropped from rest from a 75-m high bridge and lands on the log as it passes under the bridge. If the log moves with a constant speed of 5.0 m/s, what is the horizontal distance between the log and the bridge when the stone is released?

Homework Equations



Not really sure how to start off the problem, would appreciate if anyone could help me on the problem.

The Attempt at a Solution

I tried using the equation VF^2=Vi+2a(Xf-Xi)
 
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A good place to start is to find the time it takes for the stone to fall those 75m. How can you relate that time to the movement of the log?
 
Not really sur how to find the time when the only given information is that it is 75m high from the log. If I need to find the time I also need the velocity or acceleration. So how can I do that?
 
noaamari said:
Not really sur how to find the time when the only given information is that it is 75m high from the log. If I need to find the time I also need the velocity or acceleration. So how can I do that?

You know the height.

You know gravity.

x = 1/2*g*t2
 
Okay so i followed the equation and got apporoximately 3.9 secs then what equation can I use next to relate to horizontal distance?
 
How fast again was the log moving?
 

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