How is the induced EMF calculated in a circuit with a swinging pendulum gate?

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SUMMARY

The induced electromotive force (EMF) in a circuit with a swinging pendulum gate is calculated using Faraday's law of electromagnetic induction, specifically the equation \(\mathcal{E} = -\frac{1}{c} \frac{d \Phi}{dt}\), where \(\Phi\) is the magnetic flux. The circuit operates in a constant magnetic field \(B\) perpendicular to the plane of the circuit. The velocity of the pendulum is given by \(\dot{x} = \omega x_o \cos(\omega t)\), and the magnetic flux can be expressed as \(\Phi = \oint_S \mathbf{B} \cdot \mathbf{dS}\). The discussion emphasizes the need to consider changes in magnetic flux due to the pendulum's motion to accurately determine the induced EMF.

PREREQUISITES
  • Understanding of Faraday's law of electromagnetic induction
  • Knowledge of magnetic flux and its calculation
  • Familiarity with the concept of induced EMF
  • Basic principles of pendulum motion and harmonic motion
NEXT STEPS
  • Study the derivation of Faraday's law of electromagnetic induction
  • Learn how to calculate magnetic flux in varying magnetic fields
  • Explore the relationship between angular velocity and induced EMF in oscillating systems
  • Investigate the effects of changing area and angle on induced EMF
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Students studying electromagnetism, physics educators, and anyone interested in the practical applications of induced EMF in oscillating systems.

IHateMayonnaise
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Homework Statement



I just took a test, and I am very unsure of the validity of how I approached the problem. Just looking for some feedback cause this is bugging me!

There is a circuit in the xz-plane (vertical), and the circuit has on it a gate. The gate is a pendulum of length L, which swings back and forth at some velocity (given), and when it is straight up and down (theta=0) it makes contact with the other lead and completes the circuit. All the time there is a CONSTANT magnetic field B pointing normal to the circuit (+y). What is the induced EMF?

The velocity as a function of time is given:

\dot{x}=\omega x_o \cos\left(\omega t\right)



Homework Equations



\mathcal{E}=-\frac{1}{c} \frac{d \Phi}{dt}
\Phi = \oint_S \mathbf{B}\cdot\mathbf{dS}

The Attempt at a Solution



The initial conditions can be deduced fairly easily (x_o is the horizontal amplitude of the pendulum): \dot{x}(0)=0, x(0)=x_o. From the initial conditions and integrating,

x(t) = x_o\left[\sin\left(\frac{n\pi t}{2\tau}\right)+1\right]

My (probably flawed) methodology is what follows. I thought it easier to think of the circuit as staying constant (eg no gate) and the field is pulsing at some rate, which I assume to directly correspond to that of the pendulum. From this we can then calculate the induced emf. Basically from here, all I did was take the above equation, and instead of the position amplitude x_o I substituted the field amplitude B_o.

B(t) = B_o\left[\sin\left(\frac{n\pi t}{2\tau}\right)+1\right]

From here I just took the derivative and said I was done, but I feel so, so dirty and I know I goofed this up. Thoughts? Thanks yall

IHateMayonnaise
 
Physics news on Phys.org
"The magnetic flux is a measure of the number of magnetic field lines passing through an area...If the flux changes, an emf will be induced. There are therefore three ways an emf can be induced in a loop:

1. Change the magnetic field
2. Change the area of the loop
3. Change the angle between the field and the loop"

Which one applies here?More here:
http://physics.bu.edu/~duffy/py106/InducedEMF.html
 

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